Answer:
Sub to lazer beam
Step-by-step explanation:
Answer:
Following are the answers to this questions:
A) False.
B) False.
C) True.
D) True.
Step-by-step explanation:
In option A,
Let A is 
diagonal matrices that is,
![\left[\begin{array}{ccc}0&1&0\\0&0&6\\0&0&0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%261%260%5C%5C0%260%266%5C%5C0%260%260%5Cend%7Barray%7D%5Cright%5D)
here 
= 0, In this A is the nilpotent matrix and A has three values that are equal to 0 but it is not a diagonalizable matrix.
In option B,
If ![A =\left[\begin{array}{ccc}0&1\\0&0\end{array}\right]](https://tex.z-dn.net/?f=A%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%261%5C%5C0%260%5Cend%7Barray%7D%5Cright%5D)
in given value A elements are 0 and 1 as a distinct eigen value, that's why A is diagonalizable but |A| =0 its means A is not invertible, that's why it is false.
In option C,
It is given that 
where A~ D, which is A is similar to diagonal matrices, that's why it is true.
In option D,
It is given that A has eigen vector, which leases from 
. A has eigen vector and A is 
matrix, the number of A eigen values = given vector of A, that's why it is correct.
You have to divide 53 with 4 students making them each get 13 bars each
Answer:
Step-by-step explanation:
21.33 애니메이션 허벅지
