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3 years ago

At a school, students may choose one entree, one vegetable, and one dessert for lunch. The choices are listed in the table.

Mathematics

1 answer:

NeX [460]3 years ago

8 0

Would it be 24? (filler so it hits 20 characters)

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Here are two patterns made using identical rhombuses. Write one equation to show how to find the value of a and one equation t

algol13

Answer:

Equation 1

6*a = 360°

Equation 2

2*a + 2*b = 360°

a = 60°

b = 120°

Step-by-step explanation:

From the first picture we can see that 6 angles a° made a complete circle, that is, 360°. So:

6*a = 360°

a = 360°/6 = 60°

From the second picture we can see that 2 angles a° and 2 angles b° made a complete circle, then:

2*a + 2*b = 360°

2*b = 360° - 2*60°

b = 240°/2 = 120°

4 0

3 years ago

You suddenly realize that you do not like to add fractions. You ask your three best friends if they like to add fractions and th

Anettt [7]

The answer is B. deductive reasoning.

3 0

3 years ago

A Sixteen Foot ladder is leaning against a building. If the bottom of the ladder is sliding along the pavement directly away fro

Romashka [77]

Answer:

-0.69 feet per second

Step-by-step explanation:

We have dx/dt = 2 ft/sec, and we want to determine dy/dt.

x and y are related by the Pythagorean Theorem.

x²+y²=16²

Differentiate both sides of this equation with respect to t to get

$2x\frac{dx}{dt}+2y\frac{dy}{dt} =0$

$2y\frac{dy}{dt} =-2x\frac{dx}{dt}$

Divide both sides by 2y

$\frac{dy}{dt} =-\frac{x}{y}\frac{dx}{dt}$

When x = 5 ft, we have

x²+y²=16²

5²+y²=256

y²=256-25=231

therefore

y= $\sqrt{213}$

$\frac{dy}{dt} =-\frac{5}{\sqrt{213}}\frac{2 ft}{sec}$

=-0.69

The top of the ladder is sliding down (because of the negative sign in the result) at a rate of -0.69 feet per second.

5 0

3 years ago

Read 2 more answers

At what rate per cent per annum will $400 yield an interest of $78 in 1 1/2 years?

Y_Kistochka [10]

Use language that's easy-to-understand. If there's a piece of vocabulary that you feel needs clarifying, define it! 23

Step-by-step explanation:

5 0

2 years ago

Use the discriminant to determine the nature of the roots of the following equation.

kvv77 [185]

Discussion

The discriminate is b^2 - 4*a*c

The general equation for a quadratic is ax^2 + bx + c

In this equation's case

a = 1

b= -5

c = - 3

Solve

(-5)^2 - 4*(1)*(-3)

25 - (-12)

25 + 12

Note

Since the discriminate is > 0, the roots are real and different. The roots do exist and there are 2 of them.

4 0

3 years ago