128, 192, 256, 320,and 384 are the first five multiples.
Answer:
B (0.312, 0.364)
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence interval
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of 
For this problem, we have that:
1289 randomly selected American adults responded to this question. This means that
.
Of the respondents, 436 replied that America is doing about the right amount. This means that
.
Determine a 95% confidence interval for the proportion of all the registered voters who will vote for the Republican Party.
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 95% confidence interval is:
B (0.312, 0.364)
The line is starting from right side and goes thorough left .
Means
- Its starts from 1st Quadrant and goes to 3rd Quadrant.(+ve to -ve)
- Y is infinite
Hence
The solution is
![\\ \sf\longmapsto (0,\infty]](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20%280%2C%5Cinfty%5D)
First is 10 spaces, the second is 5 spaces.
Yes, find the prime factors.
4 can be written as 2*2.
g^4 can be written as g*g*g*g.
That is the prime factorization of the first expression.
4g^4 can be written as 2*2*g*g*g*g.
34 can be written as 2*17.
And again we can split up the g business: g^3 is g*g*g.
34g^3 can be written as 2*17*g*g*g.
What do these expressions have in common?
They have a 2 in common,
and three of the g's in common, ya?
Therefore the GCF(4g^4, 34g^3) = 2g^3.