Answer:
We do not have the equation for the part B, so we can not aswer it correctly.
But i will give a general answer.
We could have infinite answers always when we have more variables than linear independent equations:
This is, if we have one variable, x, we can have infinite solutions if we have no equations (or equations with no restrictions for our variable)
So if we have an equation like:
x*4 = √16*x
you can see that both sides of the equation are exactly the same, so this equation actually does not have any value, and x could take infinite different values and the equation will remain true.
If we have two variables, x and y, we will have infinite solutions if we have only one equation:
y = a*x + b
We have infinite pairs (x, y)
Two fractions between 3/5 and 4/5 are 13/20 and 11/15
Given:
In triangle MNO, angle ONM is a right angle. Angle NOM is 40 degrees and angle LMN is 50 degrees.
To find:
The value of cos(M).
Solution:
In a right angle triangle,
Draw a diagram using the given information.
In triangle MNO, angle ONM is a right angle so its opposite side MO is the hypotenuse. For vertex M, MN is the base of the triangle. So,
Therefore, the correct option is B.
<u>2x + 3y = 1</u>
<u>y = 3x + 15</u>
There's not much you can do with the first equation, because it has
two variables in it ... 'x' and 'y' . No matter how much you move them
around, you'll never be able to get either one equal to just a number.
Is there any way you could get rid of one of the variables in the first
equation, and have just 1 letter in it to solve for ?
Absolutely ! The second equation tells you something that 'y' is <u>equal</u> to,
(3x + 15). "EQUAL" is very powerful. It means that wherever you see 'y',
you can put (3x + 15) in its place, and you won't change anything or
upset anything. One thing you can do is take that (3x + 15) from the <span>
2nd</span> equation, and put it right into the first equation in place of 'y'.
You'll see how that helps as soon as you do it.
First equation: <u>2x + 3y = 1</u>
Substitute for 'y' : 2x + 3(<em>3x + 15</em>) = 1
Remove parentheses: 2x + 3(3x) + 3(15) = 1
2x + 9x + 45 = 1
Combine the terms with 'x' in them: 11x + 45 = 1
Look what you have now ! An equation with only one variable in it !
Subtract 45 from each side: 11x = -44
Divide each side by 11 : <em> x = -4</em>
You're more than halfway there. Now you know what 'x' is,
and you can use it with either equation to find what 'y' is.
-- If you use it with the first equation: <u> 2x + 3y = 1</u>
Put in the value of 'x': 2(<em>-4</em>) + 3y = 1
Remove the parentheses: -8 + 3y = 1
Add 8 to each side: 3y = 9
Divide each side by 3 : <em> y = 3</em>
-- If you use it with the 2nd equation: <u>y = 3x + 15</u>
Put in the value of 'x' : y = 3(<em>-4</em>) + 15
Remove the parentheses: y = -12 + 15
Add numbers on the right side: <em> y = 3</em> (same as the other way)
So there's your solution for the system of two equations:
<em> x = -4</em>
<em> y = 3</em>
Answer 44 is the number 36
