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Citrus2011 [14]
3 years ago
5

Complete table of values with working out

Mathematics
1 answer:
mrs_skeptik [129]3 years ago
3 0
Assume an x-value, substitute it in the equation where you find "x" and solve to find y

x = 0
y = -18

x = 1
y = -14

x = 2
y = -8

x = 3
y = 0

x = 4
y = 10
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(1CQ) Write the repeating decimal as a fraction .51
egoroff_w [7]

Answer: Your answer is 17/33! Hope this helps. If you need anymore help let me know!

8 0
3 years ago
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Lucy's family purchased one sweatshirt and 4 t-shirts for $110. Mark's family bought three sweat-shirts and 4 t-shirts for $200.
omeli [17]
T-shirt are 20 each and sweatshirt are 30
6 0
3 years ago
Evaluate N^2 + 2N 1 for N=5
Murljashka [212]

Answer:

35

Step-by-step explanation:

write 5 in N's place

5^2+2×5×1

25+10

35

8 0
3 years ago
Determine any data values that are missing from the table, assuming that the data represent a linear function.
Stells [14]

Answer:

Fill in the blank with 14

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Step-by-step explanation:

Given

The attached table

Required

Fill in the gap

Since, the table represents a linear function.

The first step is to calculate the slope of the table

m = \frac{y_2 - y_1}{x_2 - x_1}

Where

(x_1,y_1) = (1,2)

(x_2,y_2) = (2,6)

m = \frac{y_2 - y_1}{x_2 - x_1}

m = \frac{6 - 2}{2 - 1}

m = \frac{4}{1}

m=4

The equation of the table is calculated next as:

y - y_1 = m(x - x_1)

This becomes

y - 2 = 4(x - 1)

y - 2 = 4x - 4

Solve for y

y = 4x - 4+2

y = 4x -2

To fill in the blank;

The value of x is 4

So, substitute 4 for x in y = 4x -2

y = 4 * 4 - 2

y = 16 - 2

y = 14

7 0
3 years ago
Which is the simplified form of the expression ((p squared) (q Superscript 5 Baseline)) Superscript negative 4 Baseline times ((
Alexus [3.1K]

Answer:

q^{-30}

Step-by-step explanation:

Given the expression:

((p^2) (q ^5)) ^{-4} X ((p ^{-4}) (q^5)) ^{-2}

First, we open the outer brackets

=(p^{2X-4}) (q ^{5X-4})X (p ^{-4X-2}) (q^{5X-2})\\\\=(p^{-8}) (q ^{-20})X (p ^{8}) (q^{-10})\\\\$Next, we can collect like terms\\\\=p^{-8}Xp ^{8}Xq ^{-20}Xq ^{-10}\\\\$Applying addition law of indices\\\\=p^{-8+8}Xq^{-20+(-10)}\\\\=p^0 X q^{-30}\\\\=1 X q^{-30}\\\\=q^{-30}

Therefore:

((p^2) (q ^5)) ^{-4} X ((p ^{-4}) (q^5)) ^{-2}=q^{-30

8 0
3 years ago
Read 2 more answers
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