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3 years ago

5

this figure shows a right prism with a trapezoidal base, what is the sum of the areas of the four lateral (rectangular) faces of

the prism in cubic centimeters unit?

1 answer:

kirill [66]3 years ago

4 0

Step-by-step explanation:

the answer is 54 cm

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Use the law of cosines to find the length of side C.

sergij07 [2.7K]

Answer:

$\text{D. 36.64}$

Step-by-step explanation:

The Law of Sines is given by $\frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C}$ and works for any triangle.

Therefore, we have the proportion:

$\frac{c}{\sin 41.5^{\circ}}=\frac{37}{\sin 42^{\circ}},\\\\c=\frac{37\sin 41.5^{\circ}}{\sin 42^{\circ}}=36.6399945706\approx \boxed{36.64}$

8 0

3 years ago

-35 − (-12) = A) -47 B) -23 C) 23 D) 47

Alexus [3.1K]

B) -23 because a double negative is a positive so it’s -35 + 12 which is -23

5 0

3 years ago

Geometry help needed!

lilavasa [31]

Answer:

13.76

Step-by-step explanation:

Area of the whole

The area of the whole = s^2 (the firgure is a square

s = 8

Area of the whole = 8^2 = 64

Area of the unshaded part

The 2 half circles = 1 whole circle

The radius of the 1/2 circle = 4 (eight has been cut in half)

Area of two half circles = 2* (pi r^2/2)

Area of two half circles = 2 * (pi 4^2/2)

area of two half circles = 16*pi

Area of the shaded area

Area of the shaded area = area of the whole - area of the unshaded area

Area of the shaded area = 64 - 16*pi

Area of the shaded area = 64 - 3.14*16 = 13.76

4 0

3 years ago

A round-robin tournament has 66 pairings. How many teams are in the tournament?

elixir [45]

11 teams because $\frac{x(x+1)}{2}=66$ where we find x to be 11.

6 0

3 years ago

Read 2 more answers

n HP laser printer is advertised to print text documents at a speed of 18 ppm (pages per minute). The manufacturer tells you tha

Dominik [7]

Answer:

0.321 is the probability that their mean printing speed of the sample is greater than 17.99 ppm.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 17.39 ppm

Standard Deviation, σ = 4.25 ppm

Sample size = 11

We are given that the distribution of printing speed is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

P(printing speed of the sample is greater than 17.99 ppm.)

P(x > 17.99)

$P( x > 17.99) = P( z > \displaystyle\frac{17.99-17.39}{\frac{4.25}{\sqrt{11}}}) = P(z > 0.468229)\\\\P( z > 0.468229) = 1 - P(z < 0.468229)$

Calculating the value from the standard normal table we have,

$1 - 0.679 = 0321= 32.1\%\\P( x > 17.99) = 32.1\%$

Thus, 0.321 is the probability that their mean printing speed of the sample is greater than 17.99 ppm.

8 0

4 years ago