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3 years ago

Can someone help me!!!!!!!

Mathematics

1 answer:

Y_Kistochka [10]3 years ago

5 0

32. 0.19 meters 33. 7.5 links 34. 15000000000 35. 38 yards

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The unit digit of a two digit number is one less than the ten digit number. If the number is increase by 8 and then divided by t

Colt1911 [192]

The tens digit is 3; the units digit is 3-1 = 2; and the number itself is 32.

Lets simplify the problem,

Let assume the "tens" digit be x

Then the "units" difference = (x-1), according to the condition.

Hence, the number itself is N = 10x + (x-1).

Then the number N+8 is 10x + (x-1) + 8 = 10x + x + 7 = 11x + 7.

From the last statement of the problem, we have this equation

$N+8 = 8*(x+y),or11x + 7 = 8*(x+(x-1)).$

Simplify and find "x"

$11x + 7 = 8*(2x-1)11x + 7 = 16x - 87 + 8 = 16x - 11x15 = 5xx = 15/5 = 3$ .

Thus the tens digit is 3; the units digit is 3-1 = 2; and the number itself is 32.

Learn more about UNIT Problems on:

brainly.com/question/12253743

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6 0

2 years ago

The equation that describes the relationship is y =

Rainbow [258]

I just need point tbh so thanks !!

7 0

2 years ago

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WILL CHOOSE BRAINLIEST!!! Quadrilateral ABCD is congruent to quadrilateral RSTU. Without seeing the figures visually, which stat

garri49 [273]

2nd option

hope it helps...!!!

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2 years ago

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The table gives the relative frequencies of recipes that contains sugar and salt, contain at least one of those ingredients, or

tigry1 [53]

Answer-

The probability that a randomly selected recipe does not contain sugar, given that it contains salt is 22.4%

Solution-

The given table in the link shows the relative frequencies of recipes that contains sugar and salt, or contains at least one of those ingredients, or contains neither of those ingredients.

We have to find the conditional probability that the recipe doesn't contain sugar, given that it contains salt.

We know that, the conditional probability of occurrence of A given that B occurs is,

$P(A|B)=\frac{P(A\ and\ B)}{P(B)} =\frac{P(A\bigcap B)}{P(B)}$

$P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})}{P(\text{Contains salt})}$

$P(\text{Doesn't contain sugar}\ and\ \text{Contains salt})=\frac{0.15}{1} =0.15\\P(\text{Contains salt})=\frac{0.67}{1}=0.67$

Putting these values,

$P(\text{Doesn't contain sugar}\ |\ \text{Contains salt})=\frac{0.15}{0.67} =0.224=22.4\%$

5 0

3 years ago

Evaluate Combination (6,6)

andrew11 [14]

Answer:

$nCx = \frac{n!}{x! (n-x)!}$

On this case n =6 and x =6 we got:

$6C6 = \frac{6!}{6! (6-6)!} = \frac{6!}{6! 0!}= \frac{6!}{6!}=1$

Step-by-step explanation:

The utility for the combination formula is in order to find the number of ways to order a set of elements

For this case we want to find the following expression:

$6C6$

And the general formula for combination is given by:

$nCx = \frac{n!}{x! (n-x)!}$

On this case n =6 and x =6 we got:

$6C6 = \frac{6!}{6! (6-6)!} = \frac{6!}{6! 0!}= \frac{6!}{6!}=1$

8 0

2 years ago