(n/6 + 8) - 3 = 7
(n/6 + 8) - 3 + 3 = 7 + 3
n/6 + 8 - 8 = 10 - 8
n/6 = 2
(n/6)(6) = 2(6)
n = 12
Answer:
189 components must be sampled.
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
That is z with a pvalue of
, so Z = 2.575.
Now, find the margin of error M as such

Assume that component lifetimes are normally distributed with population standard deviation of 16 hours.
This means that 
How many components must be sampled so that a 99% confidence interval will have margin of error of 3 hours?
n components must be sampled.
n is found when M = 3. So






Rounding up:
189 components must be sampled.
The two fractions that added together give you a sum of -7/24 are 1/24+-8/24= -7/24
The answer is 8, hope this helps :)