Does the poem have to be about anything specific??
check the picture below.
as you may already know, tan⁻¹ function has a range of (π/2, -π/2), and therefore it will give us the negative counterpart angle, however, the positive one we can get it by going the other way, 360 - θ.
Answer:
f(2+h)=-(h+2/3)^2+1/4
f(x+h)=-(x+h-1/2)^2+1/4
Step-by-step explanation:
1. f(2+h)=(2+h)-(2+h)^2=2+h-4-4h-h^2=-h^2-3h-2=-(h^2+3h+2)
=-(h+2/3)^2+1/4
2. Let (x+h)=a, then rewrite the equation into f(a)=a-a^2.
a-a^2=-(a^2-a)=-[(a-1/2)^2-1/4]=-(a-1/2)^2+1/4.
Insert a=x+h, f(x+h)=-(x+h-1/2)^2+1/4
Answer:
<h3>Carry on learning !! </h3>
The answer to your question is 3 3/4.. i hope its right.
