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Varvara68 [4.7K]
3 years ago
6

(a) find the general solution to y^{\,\prime\prime} + 3 y^{\,\prime} = 0. give your answer as y = . . . \ . in your answer, use

c_1 and c_2 to denote arbitrary constants and x the independent variable. enter c_1 as c1 and c_2 as c2.
Mathematics
1 answer:
KengaRu [80]3 years ago
4 0
We want to solve
y'' + 3y' = 0

Solve the indicial equation.
m² + 3m = 0
m(m + 3) = 0
m = 0 or m = -3

The basic solutions are e⁰=1 and e^{-3x}.

Answer:
The general solution is
y(x) = c_{1} + c_{2}e^{-3x}

You might be interested in
For the given term, find the binomial raised to the power, whose expansion it came from: 220(5x)3(−6y)9.
sukhopar [10]
Answer: (5x - 6y)^{12}
Explanation: For a general binomial expansion, (x + y)^{n}, we know that the powers have to add up to the initial power. This means that the power of x and power of y have to add up to n. This is the binomial theorem.

To further demonstrate this, let's use:
(x + y)^{4}

We can easily expand this. Using Pascal's Triangle, we get:
(x + y)^{4} = x^{4} \cdot y^{0} + 4x^{3} \cdot y^{1} + 6x^{2} \cdot y^{2} + 4x^{1} \cdot y^{3} + x^{0} \cdot y^{4}

As we progress along the expansion, we can see that in each term, the summation of each power remains constant, namely 4.

It doesn't matter what term the binomials are, because the power summation will never change.
This is why we can say that it is raised to the 12th power, and the binomial is:
(5x - 6y).

Thus, we get: (5x - 6y)^{12}
5 0
3 years ago
Write the standard form of an equation of an ellipse subject to the given conditions.
irina [24]

Answer:

The answer is below

Step-by-step explanation:

The standard form of the equation of an ellipse with major axis on the y axis is given as:

\frac{(x-h)^2}{b^2} +\frac{(y-k)^2}{a^2} =1

Where (h, k) is the center of the ellipse, (h, k ± a) is the major axis, (h ± b, k) is the minor axis, (h, k ± c) is the foci and c² = a² - b²

Since the minor axis is at (37,0) and (-37,0), hence k = 0, h = 0 and b = 37

Also, the foci is at (0,5) and (0, -5), therefore c = 5

Using c² = a² - b²:

5² = a² - 37²

a² = 37² + 5² = 1369 + 25

a² = 1394

Therefore the equation of the ellipse is:

\frac{x^2}{1369}+ \frac{y^2}{1394} =1

6 0
2 years ago
15x-7=2+12x I need help with this
Amanda [17]

Answer:

\huge{ \boxed{ \bold{ \tt{x = 3}}}}

<h3>♁ Question : Solve for x</h3>
  • 15x - 7 = 2 + 12x

<h3>♁ Step - by - step explanation</h3>
  • \text{15x - 7 = 2 + 12x}

Move 12x to L.H.S ( Left Hand Side ) and change it's sign

➛\sf{15x - 12x - 7 = 2}

Move 7 to R.H.S ( Right Hand Side) and change it's sign

➛\sf{15x - 12x = 2 + 7}

Subtract 12x from 15x

Remember that only coefficients of like terms can be added or subtracted.

➛\sf{3x = 2 + 7}

Add the numbers : 2 and 7

➛\sf{3x = 9}

Divide both sides by 3

➛ \sf{ \frac{3x}{3}  =  \frac{9}{3}}

➛ \boxed{ \bold{ \sf{x = 3}}}

The value of x is \boxed{ \sf{3}}

✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄

☄ Now, let's check whether the value of x is 3 or not!

<h3>☥ Verification :</h3>

\sf{15x - 7 = 2 + 12x}

\dashrightarrow{ \sf{15 \times 3 - 7 = 2 + 12 \times 3}}

\dashrightarrow{ \sf{45 - 7 = 2 + 36}}

\dashrightarrow{ \sf{38 = 38}}

L.H.S = R.H.S ( Hence , the value of x is 3 ).

✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄ ✄

<h3>✒ Rules for solving an equation :</h3>
  • If an equation contains fractions ,multiply each term by the L.C.M of denominators.
  • Remove the brackets , if any.
  • Collect the terms with the variable to the left hand side and constant terms to the right hand side by changing their sign ' + ' into ' - ' and ' - ' into ' + ' .
  • Simplify and get the single term on each side.
  • Divide each side by the coefficient of variable and then get the value of variable.

Hope I helped!

Have a wonderful time ! ツ

~TheAnimeGirl

5 0
2 years ago
Anna is x years old and her sister is 5 years older. How old was her sister 5 years ago?
777dan777 [17]

Answer:

x

Step-by-step explanation:

x + 5 - 5 = x

8 0
3 years ago
Please help explanation if possible
egoroff_w [7]

Answer: x = 2 and y = -4

x + 2y = -6

x = -6-2y

Putting this in value of x in

6x + 2y = 4

6(-6-2y) + 2y = 4

-36-12y+2y = 4

-10y = 4+36

y = 40/(-10)

y = -4

Now putting this value of y in

x + 2y = -6

x + 2(-4) = -6

x -8 = -6

x = -6+8

x = 2

Therefore x = 2 and y = -4

If we put these values we can check this

x + 2y = -6

2 + 2(-4) = -6

2 -8 = -6

-6 = -6

please click thanks and mark brainliest if you like :)

7 0
2 years ago
Read 2 more answers
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