Adam has 10 blocks numbered 1 through 10. Which describes the probability of randomly choosing a block that has an even number?

1 answer:

3 0

Answer:

$\dfrac{1}{2}$

Step-by-step explanation:

Given that:

10 number of blocks which have numbers from 1 through 10.

To find:

Probability of randomly choosing a block that has an even number.

Solution:

The given set of numbers is: {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

There are a total of 5 Even numbers are {2, 4, 6, 8, 10}.

And There are a total of 5 Odd number are {1, 3, 5, 7, 9}.

Formula for probability of an event E can be observed as:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

Here, Event E is randomly choosing an even number.

Number of favorable cases = 5

Total number of cases = 10

Therefore, the required probability is:

$P(E) = \dfrac{5}{10}\\\Rightarrow P(E) = \dfrac{1}{2}$

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Andrej [43]

Answer:

Step-by-step explanation:

Alright, lets get started.

The probability that an event will occur is 2/3.

Means out of 3 times, 2 times that event will occur.

Please refer the pie chart for this, blue is the color which represents event to be occur and orange is not to be occur.

We can see, blue part is much more than orange part.

means the likelihood of event occuring is LIKELY. : Answer

Hope it will help :)

4 0

3 years ago

WINSTONCH [101]

1. X=3, 2. X=4, 3. X= 95/2

6 0

3 years ago

miv72 [106K]

Hint :-

Break the given sequence into two parts .
Notice the terms at gap of one term beginning from the first term .They are like $\dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8}$ . Next term is obtained by multiplying half to the previous term .
Notice the terms beginning from 2nd term , $4,7,10,13$ . Next term is obtained by adding 3 to the previous term .