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kow [346]
3 years ago
7

Adam has 10 blocks numbered 1 through 10. Which describes the probability of randomly choosing a block that has an even number?

Mathematics
1 answer:
Licemer1 [7]3 years ago
3 0

Answer:

\dfrac{1}{2}

Step-by-step explanation:

Given that:

10 number of blocks which have numbers from 1 through 10.

To find:

Probability of randomly choosing a block that has an even number.

Solution:

The given set of numbers is: {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

There are a total of 5 Even numbers are {2, 4, 6, 8, 10}.

And There are a total of 5 Odd number are {1, 3, 5, 7, 9}.

Formula for probability of an event <em>E</em> can be observed as:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

Here, Event <em>E </em>is randomly choosing an even number.

Number of favorable cases = 5

Total number of cases = 10

Therefore, the required probability is:

P(E) = \dfrac{5}{10}\\\Rightarrow P(E) = \dfrac{1}{2}

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The direct proportion is shown by table (B)

<h3>What is direct proportion?</h3>

Direct proportion or direct variation is the relation between two quantities where the ratio of the two is equal to a constant value.

Here the second table shows the direct proportion relation.

This is because the ratio of x/y remain same.

4/2= 7/3.5= 10/5= 11/5.5= 15/7.5 = 2/1

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VashaNatasha [74]

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Step-by-step explanation:

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3 years ago
Which of the following is equivalent to the set {Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday}?
Katyanochek1 [597]

Answer:

The answer is:  {x | x is a day of the week}

Step-by-step explanation:

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mojhsa [17]
Simplify the following:
x/((x - 2) (x + 9) (3 x - 6))

Factor 3 out of 3 x - 6:
x/(3 (x - 2) (x - 2) (x + 9))

Combine powers. x/((x - 2) (x + 9)×3 (x - 2)) = (x (x - 2)^(-1 - 1))/((x + 9)×3):
(x (x - 2)^(-1 - 1))/(3 (x + 9))

-1 - 1 = -2:
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7 0
3 years ago
Describe the translation. y = (x-5)squared +5 - y = (x-))squared +0
vovangra [49]

In functions; translations are used to move lines, points or shapes across the graph (i.e. up, down, right or left).

The translation from y = (x - 5)^2 +5 to y = (x - 0)^2 +0 is to shift y = (x - 5)^2 +5 to the left by 5 units and then downward by 5 units

The given parameters are:

y = (x - 5)^2 +5

y = (x - 0)^2 +0

Assume the first point is: y = (x - 5)^2 +5

While the second is: y = (x - 0)^2 +0

The first point is first shifted left by 5 units

The rule to this translation is: (x,y) \to (x + 5,y)

So, we have:

y' = (x - 5 + 5)^2 + 5

y' = (x - 0)^2 + 5

Next, the resulting function is shifted down by 5 units.

The rule to this translation is: (x,y) \to (x,y- 5)

So, we have:

y" = y' - 5

This gives:

y" = (x - 0)^2 + 5 - 5

y" = (x - 0)^2 + 0

Hence, the translation from y = (x - 5)^2 +5 to y = (x - 0)^2 +0 is to shift y = (x - 5)^2 +5 to the left by 5 units and then downward by 5 units

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