Answer:
The 95% confidence interval for the true average strain is between 23.94% and 28.06%.
Step-by-step explanation:
We have the standard deviation of the sample, so we use the t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 13 - 1 = 12
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 12 degrees of freedom(y-axis) and a confidence level of
. So we have T = 2.18
The margin of error is:

In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 26 - 2.06 = 23.94
The upper end of the interval is the sample mean added to M. So it is 26 + 2.06 = 28.06
The 95% confidence interval for the true average strain is between 23.94% and 28.06%.
Answer:
More nurses with a baccalaureate degree is estimated to pass the exam but this was not a significant difference.
Step-by-step explanation:
6.4$
Solution:
Divide 40 and 100(there must always be 100 when solving percentage) then it would be equal to 0.4
after it Multiply it to 16
so we get 6.4.
Answer:
In part B the answer is 71.
Step-by-step explanation:
In the 3 lines the 2 uppermost and downer most lines look like they make up a 90 degree angle.. since the first one is 19 all we have to do is 90 - 19 which equals 71. Sorry I do not know the answer to part A :(