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MrRissso [65]
3 years ago
5

Please answer it now in two minutes

Mathematics
1 answer:
Gemiola [76]3 years ago
4 0

Answer:

8.4 in

Step-by-step explanation:

Solution:-

- We consider the large right angle triangle namely, " XVW "

- We will recall all the trigonometric ratios that are applicable to all right angled triangles.

- While we are dealing with trigonometric ratios we have the following terms that needs to be correlated with the given specific problem:

            Hypotenuse ( H ): Side opposite to 90 degrees angle

            Base (B): The side adjacent to the available angle ( θ )

            Perpendicular (P): The side opposite to the available angle ( θ )

- We will go ahead and mark our respective sides as follows:

            Angle ( θ ) : 34°

            Hypotenuse ( H ) : XW = 15 in

            Base ( B ) : VW

            Perpendicular ( P ) : VX

- Now recall all the trigonometric ratios studied:

           sin ( θ ) = P / H = VX / XW

           cos ( θ ) = B / H = VW / XW

           tan ( θ ) = P / B = VX / VW

- Now choose the appropriate trigonometric ratio with two values given and one ( VX ) that needs to be determined as follows:

                             sin ( θ ) = P / H = VX / XW

                             sin ( 34° ) = VX / 15

                             VX = 15*sin ( 34° )

                             VX = 8.387 .. ( 8.4 ) in

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Someone quickly help! thanks!
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Answer:

x=23°; θ=87°

Step-by-step explanation:

These two angles create what is known as supplementary angles, or 2 angles that add up to 180°. We know this because all horizontal lines are 180° on either side. Since we know the total value of these two angles should equate to 180°, we can set up a simple equation:

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Now, using algebra, we can solve for x:

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Plugging x back into the equation, we get:

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Hope this helps!

5 0
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Hunter-Best [27]

Answer:

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So the equation is false.

4 0
3 years ago
50 – 5(4.3 – 1.3) ÷ 0.5
marissa [1.9K]

Answer:

(0.5, 1.3)(0.5, 1.3)

Step-by-step explanation:

Given equations are:

As we can see that the given equations are linear equations which are graphed as straight lines on graph. The solution of two equations is the point of their intersection on the graph.

We can plot the graph of both equations using any online or desktop graphing tool.

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Keywords: Linear equations, variables

4 0
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disa [49]

Answer:

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