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ElenaW [278]
3 years ago
12

1k + 9>30 Plis ayúdenme

Mathematics
1 answer:
Leni [432]3 years ago
7 0

Answer:

Step-by-step explanation:

1k +9 > 30

1k +9 -9 > 30 -9

1k > 21

k > 21

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Which of the following is the correct factored form for the given equation? 2x^2+8x+6=0
3241004551 [841]
It would be 2(x+3)(x+1)=0

Explanation:
I used factor by grouping. You multiply the first term (2) by the last term (6). This gives you 12 then take the factors of 12 that add up to the middle term 8. You get 6 and 2.
It should look like 2x^2+6x+2x+6=0
when you do factor by grouping you factor the first two terms and then the last two terms separately. So you get (2x+2) and (x+3). (2x+2) could be factored into 2(x+1). Then you put everything together and get 2(x+3)(x+1)=0
6 0
3 years ago
Solve the following compound inequality: 3<-2x-137.
yarga [219]

Answer:

Step-by-step explanation:

Here you go mate

PEDMAS

STEP 1

3<-2x-137  equation

STEP 2

3<-2x-137  simplify by reversing equation

-2x-137>3

STEP 3

-2x-137>3   simplify

-2x>140

step 4

-2x>140   look for a number that can divide the two numbers like 2

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1>-70

answer

x>-70

3 0
3 years ago
Solve 4(2a-1) = -10(a-5)
densk [106]
Firstly, you've got to expand the brackets, this becomes;
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You've then got to eliminate the -10a and you do this by adding 10a to both sides,
This then becomes 18a-4=50
You've then got to add 4, to eliminate this, which then becomes 18a=54
You've then got to divide both sides by 18, and this becomes 3.
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Hope this helps :)
4 0
3 years ago
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The temperature was 80 °F and then fell 20 °F. What is the new temperature?
Goshia [24]
The new temperature is 60 degrees
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3 years ago
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ind the present value that will grow to ​$4000 if the annual interest rate is ​8.5% compounded quarterly for 9 yr.
frozen [14]

Answer:

  $1876.31

Step-by-step explanation:

The present value can be found using the compound interest formula.

<h3>Present value</h3>

The formula for the future value of an investment of P earning annual interest rate r compounded n times per year for t years is ...

  FV = P(1 +r/n)^(nt)

Filling in the known values gives ...

  4000 = P(1 +0.085/4)^(4·9) = P(1.02125^36)

Then the amount to be invested is ...

  P = 4000/1.02125^36 ≈ 1876.31

The present value is $1876.31.

4 0
2 years ago
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