I'm going to assume that you are trying to find the two numbers. Based on the information in the problem, we can create the following equations (where 
and 
are the two numbers):
We have a systems of equations. In this case, it would be easier to use elimination by adding vertically. This produces the result:
To find , substitute the value for into one of the earlier equations:
The two numbers are 12 and 18.
Answer: Answer A: Both classes have a range of 45
Step-by-step explanation:
above the two graphs we can see a number line ranging from 50-100
bellow that, we can see 2 box and whisker plots, one for second period and one for fourth period. the larger rectangular boxes show all the number results, the line in between them states the average result. Both lines have starting points at 55 and ending points at 100.
100-55=45 45 being the range. Since 2nd and 4th both share the same range answer A could possibly be correct
B is wrong because 2nd period has a median of 90
C is wrong because no periods have a median of 100
D is wrong because most of the students scored an 85+
conclusion: answer A is correct
Answer:
The first one is missing (d - 9) so it would be 5(d -9) or when you factor it out 5d - 45
In the second one (d + 7) is missing so it will be 8d(d + 7) so if you factor that out you will receive 8d^2 + 56
Step-by-step explanation:
3d^2 + 18d -21 =(3d -3)( d + 7)
3d^2 -30d +27 =(3d -3)(d - 9)
Answer:
no geniune idea
Step-by-step explanation:
