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worty [1.4K]
4 years ago
8

Please can any one help on these two

Mathematics
2 answers:
frutty [35]4 years ago
7 0
Question 1 is C and question 2 is A
Free_Kalibri [48]4 years ago
5 0
For the first question it’s C and for the second question it’s A
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Circle M is circumscribed about right triangle ABC with legs 6 meters and 8 meters.
pashok25 [27]

ABC is a right triangle, so AC has length given by

AC^2=(6\,\mathrm m)^2+(8\,\mathrm m)^2\implies AC=\sqrt{100\,\mathrm m^2}=10\,\mathrm m

Then the circumference of circle M is 10\pi\,\mathrm m.

4 0
3 years ago
If k represents a number, then write an expression for the ratio of 3 less than k to 2 more than k
Svetradugi [14.3K]

Answer:

k - 3 : k + 2

Step-by-step explanation:

3 less than k = k - 3

2 more than k = k + 2

Ratio of 3 less than k to 2 more than k

In ratios, the word 'to' is represented as a colon :

k - 3 : k + 2

Hope this helps :)

3 0
2 years ago
What is the midpoint of the line segment with endpoints (-2, -4) and (4,6)?
prohojiy [21]

Answer:

(1,1)

Step-by-step explanation:

use the midpoint formula to find the midpoint of the line segment

7 0
4 years ago
If
likoan [24]

It's easy to show that 7\tan(4x) is strictly increasing on x\in\left[0,\frac\pi8\right]. This means

M = \max \left\{7\tan(4x) \mid \dfrac\pi{16} \le x \le \dfrac\pi{12}\right\} = 7\tan(4x) \bigg|_{x=\pi/12} = 7\sqrt3

and

m = \min \left\{7\tan(4x) \mid \dfrac\pi{16} \le x \le \dfrac\pi{12}\right\} = 7\tan(4x) \bigg|_{x=\pi/16} = 7

Then the integral is bounded by

\displaystyle 7\left(\frac\pi{12} - \frac\pi{16}\right) \le \int_{\pi/16}^{\pi/12} 7\tan(4x) \, dx \le 7\sqrt3 \left(\frac\pi{12} - \frac\pi{16}\right)

\implies \displaystyle \boxed{\frac{7\pi}{48}} \le \int_{\pi/16}^{\pi/12} 7\tan(4x) \, dx \le \boxed{\frac{7\sqrt3\,\pi}{48}}

7 0
2 years ago
A sailfish can swim u to 68 miles per hour. At this rate, how far can a sailfish swim in 1/4 hour?
Novay_Z [31]

Answer:

C. 17 miles

Step-by-step explanation:

Divide 68 by 4 since it is a fourth of an hour

6 0
3 years ago
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