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2 years ago

14

What is the sum of the zeros of the equation y = 2x2+5x−3

1 answer:

ch4aika [34]2 years ago

4 0

Answer:

2×2+5×-3= -11

Step-by-step explanation:

que te pjefa ayudar

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Please someone answer these 2 questions

saveliy_v [14]

1. C
2.A
Hope this helps, good luck :D

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2 years ago

There are 16 boys and 19 girls in a class. The teacher calls the

san4es73 [151]

Answer:

1/12/2121 precent

Step-by-step explanation:

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2 years ago

Can I get a help please

iogann1982 [59]

Answer:

middle graph

Step-by-step explanation:

Soluton

The second (middle ) graph is the only one that works.

First of all when you simplicity the right, you get y = x^2 - 1). That means that x does not go through 0,0. If you put x = 0 into x^ - 1 = 0, you get - 1. So on that basis alone both the first and third graphs are incorrect.
Second, both xs in the factors are plus, so x^2 is plus, which means the graph opens upward.

6 0

1 year ago

Which is the equation of a hyperbola centered at the origin with x-intercept +\- 3 and asymptote y=2x

Radda [10]

Answer:

${\dfrac{x^{2}}{9} - \dfrac{y^{2}}{36} = 1}$

Step-by-step explanation:

The hyperbola has x-intercepts, so it has a horizontal transverse axis.

The standard form of the equation of a hyperbola with a horizontal transverse axis is $\dfrac{(x - h)^{2}}{a^{2}} - \dfrac{(y - k)^{2}}{b^{2}} = 1$

The center is at (h,k).

The distance between the vertices is 2a.

The equations of the asymptotes are $y = k \pm \dfrac{b}{a}(x - h)$

1. Calculate h and k. The hyperbola is symmetric about the origin, so

h = 0 and k = 0

2. For 'a': 2a = x₂ - x₁ = 3 - (-3) = 3 + 3 = 6

a = 6/2 = 3

3. For 'b': The equation for the asymptote with the positive slope is

$y = k + \dfrac{b}{a}(x - h) = \dfrac{b}{a}x$

Thus, asymptote has the slope of

$\begin{array}{rcl}m& =& \dfrac{b}{a}\\\\2& =& \dfrac{b}{3}\\\\b& =& \mathbf{6}\end{array}$

4. The equation of the hyperbola is

$\large \boxed{\mathbf{\dfrac{x^{2}}{9} - \dfrac{y^{2}}{36} = 1}}$

The attachment below represents your hyperbola with x-intercepts at ±3 and asymptotes with slope ±2.

7 0

2 years ago

Find the scale factor of the smaller figure to the larger figure

3241004551 [841]

(smaller length measure) to (larger length measure)
3 to 9 or 6 to 18
reduces to 1 to 3 or $\frac{1}{3}$

5 0

2 years ago

Read 2 more answers