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Ivahew [28]
3 years ago
5

Please right now I need help

Mathematics
2 answers:
zzz [600]3 years ago
7 0
Hello is the 3 i think
ollegr [7]3 years ago
6 0

Answer:

3

Step-by-step explanation:

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1+1+1*0+1=x<br><br> what would it be
exis [7]
It’s x=3
explanation: well you multiply by 0, then add the numbers, & move the variable to the left
7 0
3 years ago
The phone lines to an airline reservation system are occupied 40% of the time. Assume that the events that the lines are occupie
nikitadnepr [17]

Answer:

a) P(X=3)

And we can use the probability mass function and we got:

P(X=3) = (10C3) (0.4)^3 (1-0.4)^{10-3} = 0.215

b) For this case we want this probability:

P(X \geq 1)

and the probability that the one call would be not occupied is 1-0.4=0.6

And if we use the complement rule we got:

P(X \geq 1)= 1-P(X

P(X=0) = (10C0) (0.6)^0 (1-0.6)^{10-0} = 0.000105

P(X \geq 1)= 1-P(X

c) E(X) = np = 10*0.4 = 4

Step-by-step explanation:

Previous concepts  

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".  

a. What is the probability that for exactly three calls, the lines are occupied?

Let X the random variable of interest, on this case we now that:  

X \sim Binom(n=10, p=0.4)  

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

And for this case we want this probability:

P(X=3)

And we can use the probability mass function and we got:

P(X=3) = (10C3) (0.4)^3 (1-0.4)^{10-3} = 0.215

b. What is the probability that for at least one call, the lines are not occupied?

For this case we want this probability:

P(X \geq 1)

and the probability that the one call would be not occupied is 1-0.4=0.6

And if we use the complement rule we got:

P(X \geq 1)= 1-P(X

P(X=0) = (10C0) (0.6)^0 (1-0.6)^{10-0} = 0.000105

P(X \geq 1)= 1-P(X

c. What is the expected number of calls in which the lines are all occupied?

For this case the expected value is given by:

E(X) = np = 10*0.4 = 4

8 0
3 years ago
11 X 11= 4, 12x12=9,13x13=?
likoan [24]
11x11 => (1 +1)(1 +1) = 2x2 =4 

<span>12x12 => (1 +2)(1 +2) = 3x3 = 9 </span>

<span>13x13 => (1 +3(1 +3) = 4x4 = 16</span>
6 0
4 years ago
Read 2 more answers
Find the area of these composite shapes
yanalaym [24]
The answer would be 360 cm
5 0
3 years ago
Read 2 more answers
Solve 9 - c = 17d for c
k0ka [10]

Answer:

c = 9 - 17d

Step-by-step explanation:

9-c = 17d

9-c+c= 17d + c (add c to both sides)

9 = 17d + c (Simplify)

9 - 17d = 17d - 17d + c (subtract 17d from both sides)

9 - 17d = c (Simplify)

5 0
3 years ago
Read 2 more answers
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