The answer is 7 because 2 to 5 is 3 and -2 to 5 I 7
Answer:
L = 5 m
Step-by-step explanation:
The ladder, the vertical wall and the ground form a right triangle. We call A and B the ends points of the ladder ( at the wall, and the ground)
If we call L the lenght of the leadder, we get
L² = y² + x²
Taking derivatives on both sides of the equation
0 = 2y Dy/dt + 2x Dx/dt
We know that Dy/dt = - 0,675 m/s (is sliding down , is decreasing)
And when x = 3 m Dx/dt = 0,9 m/s
So we can get y
0 = 2y*( -0,675) + 2*3*0,9
1,35y = 5,4
y = 5.4 /1,35 ⇒ y = 4
And L² = y² + x² ⇒ L = √ (4)² + (3)² ⇒ L √16 + 9
L = 5 m
Answer: The maximum area that could be enclosed would be 92,450 square feet.
To find the maximum area, we have to write an equation relating the different sides. For our shape, we will have 2 widths and 1 length that runs parallel to the creek.
Let the widths equal x. Then, the length would be 86 - 2x.
So the area of the shape is: A = x(860 - 2x)
This is a quadratic equation with a vertex at (215, 92450).
Therefore the width should be 215 to get the maximum area of 92,450 square feet.
The sum of the exterior angles is 360 deg. Each interior angle is supplementary to its corresponding exterior angle, so
So you have