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wolverine [178]
3 years ago
11

Is this mapping a function or not a function? Explain.

Mathematics
2 answers:
Maru [420]3 years ago
4 0

Answer:

for every x there is just one y

Step-by-step explanation:

i just learned about this

:) ;)

lorasvet [3.4K]3 years ago
3 0

Answer:

a relation in which for every input there is exactly one output (for every x there is just one y)

Step-by-step explanation:

since you didn't give what was supposed to be a mapping function or not thats the best i can do

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A volunteer has 12 pounds of birdseed to put in the bird feeders in all of the city parks. There are 13/4 cups of birdseed in a
kozerog [31]

Answer:

\large \boxed{28}

Step-by-step explanation:

1. Calculate the number of cups

\text{Cups} = \text{12 lb}\times\dfrac{1\frac{3}{4} \text{ cups}}{\text{1 lb}} =12\times\dfrac{\text{7 cups}}{4} = 3\times7\text{ cups}= \text{21 cups}

2. Calculate the number of bird feeders

\text{ Feeders}= \text{21 cups} \times \dfrac{\text{1 feeder}}{\frac{3}{4}\text{ cup}}=\text{21 cups} \times \dfrac{\text{4 feeders}}{\text{3 cups}} = 7 \times \text{ 4 feeders}\\\\= \textbf{28 feeders}\\\text{The volunteer can fill $\large \boxed{\textbf{28 feeders}}$}

5 0
3 years ago
John ordered a large three topping pizza for $7. 50 and a large 8 topping pizza for $10. Write an equation in slope-intercept fo
yKpoI14uk [10]

to get the equation of any straight line, we simply need two points off of it, well, let's use the provided values hmmm

\begin{array}{ccll} \stackrel{toppings}{x}&\stackrel{cost}{y}\\ \cline{1-2} 3 & 7.50\\ 8& 10 \end{array} \qquad\implies \qquad (\stackrel{x_1}{3}~,~\stackrel{y_1}{7.50})\qquad (\stackrel{x_2}{8}~,~\stackrel{y_2}{10}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{10}-\stackrel{y1}{7.50}}}{\underset{run} {\underset{x_2}{8}-\underset{x_1}{3}}}\implies \cfrac{2.5}{5}\implies \cfrac{~~ \frac{25}{10}~~}{5}\implies \cfrac{25}{50}\implies \cfrac{1}{2}

\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{7.50}=\stackrel{m}{\cfrac{1}{2}}(x-\stackrel{x_1}{3})\implies y-\cfrac{750}{100}=\cfrac{1}{2}(x-3) \\\\\\ y-\cfrac{15}{2}=\cfrac{1}{2}x-\cfrac{3}{2}\implies y=\cfrac{1}{2}x-\cfrac{3}{2}+\cfrac{15}{2}\implies y=\cfrac{1}{2}x-6

3 0
2 years ago
How to do number 2 ?
kakasveta [241]

you will need to add.

7 0
3 years ago
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