Just draw a triangle(front view) and the slant/inclined sides of it are known to be 8 and you found out radius as 3.26. so mark the diameter by doubling radius.
so the material required would be a slice(like pizza slice) of a circle of radius= 8 and arc length = circumference given ,that is 20.5
now using this find the area of sector/slice. its the answer to the last bit.
now coming to next question, go to the kitchen and take any can and measure its dia and height by using a scale. and you might already know the formula to find the suface area of cylinder.
Answer: X intercept: (-4,0) Y Intercept: (0,-3)
Step-by-step explanation: i dont know if thats how it was suppose to be done or not but that is just the intercepts for it.
Answer:
18
Step-by-step explanation:
3/5 x 30
(3 times 30)divided by 5
= 18 children are going.
Hope this helps:-)
Answer:
12
Step-by-step explanation:
x=2 was multiplied by 4 to get to x=8 so you multiply y=3 by 4 to make it y=12
<span><span><span>1. An altitude of a triangle is a line segment from a vertex perpendicular to the opposite side. Find the equations of the altitudes of the triangle with vertices (4, 5),(-4, 1) and (2, -5). Do this by solving a system of two of two of the altitude equations and showing that the intersection point also belongs to the third line. </span>
(Scroll Down for Answer!)</span><span>Answer by </span>jim_thompson5910(34047) (Show Source):You can put this solution on YOUR website!
<span>If we plot the points and connect them, we get this triangle:
Let point
A=(xA,yA)
B=(xB,yB)
C=(xC,yC)
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Let's find the equation of the segment AB
Start with the general formula
Plug in the given points
Simplify and combine like terms
So the equation of the line through AB is
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Let's find the equation of the segment BC
Start with the general formula
Plug in the given points
Simplify and combine like terms
So the equation of the line through BC is
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Let's find the equation of the segment CA
Start with the general formula
Plug in the given points
Simplify and combine like terms
So the equation of the line through CA is
So we have these equations of the lines that make up the triangle
So to find the equation of the line that is perpendicular to that goes through the point C(2,-5), simply negate and invert the slope to get
Now plug the slope and the point (2,-5) into
Solve for y and simplify
So the altitude for vertex C is
Now to find the equation of the line that is perpendicular to that goes through the point A(4,5), simply negate and invert the slope to get
Now plug the slope and the point (2,-5) into
Solve for y and simplify
So the altitude for vertex A is
Now to find the equation of the line that is perpendicular to that goes through the point B(-4,1), simply negate and invert the slope to get
Now plug the slope and the point (-4,1) into
Solve for y and simplify
So the altitude for vertex B is
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Now let's solve the system
Plug in into the first equation
Add 2x to both sides and subtract 2 from both sides
Divide both sides by 3 to isolate x
Now plug this into
So the orthocenter is (-2/3,1/3)
So if we plug in into the third equation , we get
So the orthocenter lies on the third altitude
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