Ask question

Ask question

All categories

1 year ago

13

Rewrite the fraction in the sentence below as a percentage.

1 answer:

scoray [572]1 year ago

8 0

Answer:

86%

Step-by-step explanation:

A percentage is a number or a ratio expressed as a fraction over 100. For example, 50% in fraction form is known as 50/100. 45% is known as 45/100.

Lets say the fraction was 43/50. We already know that a percentage is a number expressed as a fraction over 100, in order to convert this fraction into a percentage, we would have to multiply the denominator by a certain number in order to make it 100.

43/50 = x/100

If we multiply 50 × 2 = 100, so now we have to do the same for the numerator, and also multiply it by 2.

43 × 2 = 86

50 × 2 = 100

Now we know that the fraction is 86/100, now in order to convert it into percantage form, it would just be 86%

<u>T</u><u>h</u><u>e</u><u> </u><u>a</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u><u> </u><u>i</u><u>s</u><u> </u><u>8</u><u>6</u><u>%</u>

You might be interested in

If f(x) = 2x² +5 and g(x)=x2-2, find (f-g)(x).

Rufina [12.5K]

Answer:D. x^2+7

Step-by-step explanation:

If f(x) = 2x² +5 and g(x)=x2-2, find (f-g)(x).A. x^2+3B. 3x^2+3C. 3x^2+7D. x^2+7

4 0

1 year ago

ASAP h(t)=-5t^2+5t+10<br><br> Please help me find roots and roots equation

Alex

Answer:

t = -1, 2

Step-by-step explanation:

Step 1: Define

h(t) = -5t² + 5t + 10

Step 2: Factor

h(t) = -5(t² - t - 2)

h(t) = -5(t - 2)(t + 1)

Step 3: Find roots

0 = -5(t - 2)(t + 1)

0 = (t - 2)(t + 1)

t - 2 = 0

t = 2

t + 1 = 0

t = -1

8 0

2 years ago

5.62 x 10^2 in standard notation ??

Lyrx [107]

The answer is five hundred sixty.

6 0

2 years ago

Can someone help me please

Ahat [919]

This is a black screen!!!!

5 0

2 years ago

State the domain restriction(s) in interval notation of \displaystyle f\left(g\left(x\right)\right)f(g(x)) given: \displaystyle

DENIUS [597]

Answer:

The interval notation for the domain is $[\frac{23}{3},\infty ]$ .

Step-by-step explanation:

Consider the provided information.

It is given that $\:f\left(x\right)=\sqrt{3x-2},\:\text{ and }\:g\left(x\right)=x-7$

We need to find the value of $f\left(g\left(x\right)\right)$ .

Put the value of g(x) in $f\left(g\left(x\right)\right)$ .

$f\left(g\left(x\right)\right)=f(x-7)$ ....(1)

Now, put x=x-7 in $\:f\left(x\right)=\sqrt{3x-2}$

$\:f\left(x-7\right)= \sqrt{3(x-7)-2}$

$\:f\left(x-7\right)= \sqrt{3x-21-2}$

$\:f\left(x-7\right)= \sqrt{3x-23}$

From equation 1.

$f\left(g\left(x\right)\right)=\:f\left(x-7\right)= \sqrt{3x-23}$

The domain of the function is the set of input values for which a function is defined.

Here, the value of $3x-23$ should be greater or equal to 0 as the square root of a negative number is not real.

Domain= $3x-23\geq0$

$x\geq\frac{23}{3}$

The value of x is all real number greater than $\frac{23}{3}$ .

Hence, the interval notation for the domain is $[\frac{23}{3},\infty ]$ .

7 0

2 years ago