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gogolik [260]
3 years ago
9

Pls help me find the sum ❣️

Mathematics
1 answer:
Natasha2012 [34]3 years ago
4 0

Answer:

Step-by-step explanation:

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Draw a histogram for the intervals 16-18,19-21, 22-24, and 25-27 using the following data: 26, 16, 27
Kitty [74]

Answer with explanation:

Class Interval             Variate         Frequency

16-18                              16                     1

19-21                               0                     0

22-24                               0                    0

25-27                              26,27              2

8 0
3 years ago
A flower pot's base has six sides that are all the same length. Each side measures x - 6 units. The base's perimeter is 78 units
Nadusha1986 [10]
The answer would x=19 units
5 0
2 years ago
Find the value of `x´ in the given parrallelogram.​
Ganezh [65]
X=9

3x-12=x+6
2x-12=6
2x=18
X=9
7 0
2 years ago
Read 2 more answers
Solve for m please. No explanation needed thank you.
liq [111]

Answer is below.

<em>(Note to asker: Lack of explanations can get my answer deleted)</em>

<em />

<u><em>Step 1</em></u>

We'll to isolate the variable, but to do that, get rid of the coefficient that multiplies it.

To do that, divide both sides by 22.

\frac{22m}{22}=\frac{22}{10}

<em><u>Step 2.</u></em>

Now we have divided both sides by 22, but we'll need to reduce the fraction \frac{22m}{22}.

We can reduce the fraction by dividing the factors that are in the numerator and denominator.

That being said, 22 appears both in the numerator and denominator.

\frac{22m}{22}=m=\frac{2\times5}{2\times11}

<u><em>Step 3</em></u>

Now, for \frac{2\times5}{2\times11}, we'll need to reduce it to the lowest terms. Like in the 2nd step, we'll divide factors that are in the numerator and denominator.

That being said, 2 appears both in the numerator and denominator.

Hence, M = 5/11

3 0
3 years ago
Simplify (5n^4)^−3. Assume n ≠ 0.
tekilochka [14]
Since the exponent (-3) is negative, flip the expression to: 1/(5n^4)^3.

Notice how the negative exponent becomes positive as you flip it.

Now evaluate the powers in the denominator: 1/((5^3)(n^4)^3

I separated the constant (5) from the variable (n) to show you how the powers are evaluated.

1/(5x5x5)(nxnxnxn)(nxnxnxn)(nxnxnxn)
—-> the power four means that there are 4 multiples of n in the parentheses. The power 3 corresponds to how many groups.

1/(125)(n^12)

= 1/125n^12
6 0
3 years ago
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