The answer to the question
Answer:
The first term is 3. The common difference is 2.
Step-by-step explanation:
The first term is x.
The common difference is d.
The second term is x + d.
3rd term: x + 2d
4th term: x + 3d
7th term: x + 6d
"The fourth term of an Arithmetic Sequence is equal to 3 times the first term"
x + 3d = 3 * x Eq. 1
"the seventh term exceeds twice the third term by 1"
x + 6d = 2(x + 2d) + 1 Eq. 2
Simplify Eq. 1:
2x = 3d
Simplify Eq. 2:
x + 6d = 2x + 4d + 1
x = 2d - 1
Multiply both sides of the last equation by 2.
2x = 4d - 2
2x = 3d (simplified Eq. 1)
Since 2x = 2x, then the right sides are equal.
3d = 4d - 2
d = 2
2x = 3d
2x = 3(2)
2x = 6
x = 3
Answer: The first term is 3. The common difference is 2.
Answer:
1.) Triangle is <u>1/2 x b x h (Which is option C)</u>
2.) Rhombus is<u> ½ × d1 × d2. (Which is option A)</u>
3.) Trapezoid is <u>½(b 1+b 2)h or (b1 + b2)h/2 (Which is option B)</u>
4.) Parallelogram is <u>base x height (Which is option D)</u>
Step-by-step explanation:
6>y , i don’t get the other one cuz it would just be y+(a number)
Answer:
Step-by-step explanation:
The function for this problem is: h(t) = -16(t)^2 + vt + s h= the height t= time v= velocity s= starting height With the information given, we know that the starting height is 0, since it was from the ground, and the velocity of the ball is 35 feet per second. Inserting the these information into the equation, we get: h(t) = -16(t)^2 + 35t Now the question asks to find the maximum height. It can be done by using a grapher to graph the maximum of the parabola. It could also be done by finding the vertex, which would be the maximum, of the graph by using x= -b/(2a), where b is equal to 35 and a is equal to -16. We get x=35/32, the x-value of where the vertex lies. You can use this value as the t-value in the previous equation to find the h-value of the vertex. When you do, you get h= 19.1 feet, or answer D.
hope this helps
