The coordinates of point K(7, 0).
Given, JK has midpoint M(7, 2).
And, the coordinates of point J(7, 4).
We have to find the coordinates of point K.
As M is the midpoint, therefore by using the midpoint formula.
(xₙ + yₙ) = (x₁ + x₂/2 , y₁ + y₂/2)
Using x-coordinates,
xₙ = x₁ + x₂/2
7 = x₁ + 7/2
14 = x₁ + 7
or x₁ = 7
Nos using y-coordinates,
yₙ = y₁ + y₂/2
2 = y₁ + 4/2
4 = y₁ + 4
y₁ = 0
Therefore, the coordinates of point K(7, 0).
The coordinates of J(7, 4); K(7, 0); and M(7, 2).
To learn more about midpoints, visit: brainly.com/question/4637646
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3) Vertex: (-7, 0) Axis of Symmetry: x=-7
6) Vertex: (-2, -1) Axis of Symmetry: x=-2
Area of a square: s^2
Because we know the length of one side, we can multiply it by itself to find the area.
(3x - 6)(3x - 6)
9x^2 - 18x - 18x + 36
Combine like terms.
9x^2 - 36x + 36
<h3>The correct answer is A, or the first answer. </h3>
