Guys Help please asapppp
1 answer:
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There are two -main- approaches to answer this problem. By using the sine identity, or applying law of sines.
We'll do the sine trig. identity, as it is the most effective.
Given an angle '
' in a right triangle, '
' is defined as the opposite side of the triangle to the given angle, over the triangle's hypotenuse.
So, for this setup:
Now, we solve for x:
So, answer is 3.4
We'll do the sine trig. identity, as it is the most effective.
Given an angle '
So, for this setup:
Now, we solve for x:
So, answer is 3.4
Answer:
a) <u>90 pitches total</u>
b) <u>27 hits</u>
c) <u>63 pitches (either ball or strike)</u>
Step-by-step explanation:
Every pitch is:
BALL, STRIKE, HIT
(one of the 3)
a)
Given, 60% of total pitches were strikes, that is 54 of them. So we can say:
54 is 60% of total
Let total be "t", so we can write:
54 = 60% * t
Solving for "t":
Hence, <u>total 90 pitches</u>
<u></u>
b)
60% = strikes
10% = balls
Remaining = 60 + 10 = 70
100 - 70 = 30%
So, 30% of total were hits.
30% of 90
0.3 * 90
<u>27 hits</u>
<u></u>
c)
We know 10% were balls, so
0.10 * 90 = 9 balls
We know 54 were strikes
So, either ball or strike = 9 + 54 = 63
<u>63 pitches (either ball or strike)</u>