Answer:
Probability that their mean credit card balance is less than $2500 is 0.0073.
Step-by-step explanation:
We are given that a bank auditor claims that credit card balances are normally distributed, with a mean of $3570 and a standard deviation of $980.
You randomly select 5 credit card holders.
Let<em> </em><em> = </em><u><em>sample mean credit card balance</em></u>
The z score probability distribution for sample mean is given by;
Z = ~ N(0,1)
where, = population mean credit card balance = $3570
= standard deviation = $980
n = sample of credit card holders = 5
Now, the probability that their mean credit card balance is less than $2500 is given by = P(<em> </em>< $2500)
P(<em> </em>< $2500) = P( < ) = P(Z < -2.44) = 1 - P(Z 2.44)
= 1 - 0.9927 = 0.0073
The above probability is calculated by looking at the value of x = 2.44 in the z table which has an area of 0.9927.
Therefore, probability that their mean credit card balance is less than $2500 is 0.0073.
Gina will earn at least 30% of intreat in the next 2 year .
Answer:
She rewrote the problem without parentheses: x3+ 2x2 - x + x3 – 2x2 +6
Step-by-step explanation:
It looks like she didn't fully distribute the -
(x3 + 2x2 - x)-(-x3 + 2x2 + 6) :Original
x3+ 2x2 - x + x3 – 2x2 +6 :Changed
~
(x3 + 2x2 - x)-(-x3 + 2x2 + 6)
x3 + 2x2 - x + x3 - 2x2 - 6
x3 + x3 + 2x2 - 2x2 -x - 6
2x3-x-6
I hope this helps ^-^
Answer:
52.08°
Step-by-step explanation:
Law of sine: =
93*14=25x
1302=25x
52.08=x
Answer:
Scale using for plan ⇒ 1 m = 4 cm
Step-by-step explanation: