All categories

4 years ago

I WILL GIVE BRAINLIEST TO WHOEVER IS CORRECT.

Mathematics

1 answer:

Alex777 [14]4 years ago

3 0

The x-intercept is where your line first touches the x-axis. The y-intercept is the same thing but is when the line touches the y-axis. The total amount of money would go in the box that says y-intercept. The number of cups of lemonade that must be sold to break even would go in the x-intercept box. By break even they mean to get out of debt.

You might be interested in

If c is the measure of hypotenuse, find the missing measure of the side of the right triangle: a = 8, b = _______, c = 17.

SSSSS [86.1K]

Answer: b = 15, the perimeter is 40, and the area is 60.

Step-by-step explanation: First we need to find b. Using the Pythagorean Theorem, we know what 8^2 + b^2 = 17^2. This is the same as 64 + b^2 = 289. Subtract 64 from each side and we get b^2 = 225, which happens to be 15^2, so b=15. Now that we have b, we can add 8 + 15 + 17 to get the perimeter, 40. The area comes from 1/2*base*height, so 1/2 * 8 * 15. The area of the triangle is 60.

4 0

3 years ago

Abbey wants to use her savings of $1325 to learn yoga. The total charges to learn yoga include a fixed registration fee of $35 a

Alika [10]

It’s 26

HOW?
1325 - 35 (registration)
1290 - 1250 (AKA 25) for monthly

25 + 1 = 26
Abbey can spend her savings for 26 months of yoga

make sure to mark brainliest if helped enough!

4 0

3 years ago

NA = 360

matrenka [14]

Answer:

I think the answer is d.)120

5 0

3 years ago

n rectangle ABCD, point E lies half way between sides AB and CD and halfway between sides AD and BC. If AB=3 and BC=11, what is

ArbitrLikvidat [17]

*see attachment for clearer diagram

Answer:

16.5

Step-by-step explanation:

BC = 11

AB = 3

Area of the shaded region = area of ∆AEB + area of ∆CED

Area of a triangle is given as,

A = ½*base*height

Find the area of each triangle and add together

✔️Area of ∆AEB = ½*bh

Where,

base (b) = 3

height (h) = ½(BC) = ½(11) = 5.5

Area of ∆AEB = ½*3*5.5 = 8.25

✔️Area of ∆CED = ½*bh

Where,

b = 3

h = ½(BC) = ½(11) = 5.5

Area of ∆CED = ½*3*5.5 = 8.25

✅Area of the shaded region = area of ∆AEB + area of ∆CED

= 8.25 + 8.25

= 16.5

3 0

3 years ago

When a store had Sold 2/5 of the shirts that were on display, they brought out another 30 from the stockroom. The store likes to

Inga [223]

Answer:

Part A) 3/5 is the total number of shirts remaining on display after selling 2/5

Part B) $x \geq 200$ (All real whole numbers greater than or equal to 200 shirts)

Part C) Initially on display were the amount of 200 or more shirts

Step-by-step explanation:

Let

x-------> total number of shirts on display

we know that

The inequality that represent the situation is

$(1-\frac{2}{5})x+30 \geq 150$

$(\frac{3}{5})x+30 \geq 150$

Part A) Explain what 3/5 means in the inequality

3/5 is the total number of shirts remaining on display after selling 2/5

Part B) Solve the inequality

we have

$(\frac{3}{5})x+30 \geq 150$

Subtract 30 both sides

$(\frac{3}{5})x \geq 150-30$

$(\frac{3}{5})x \geq 120$

Multiply by 5/3 both sides

$x \geq 120(5/3)$

$x \geq 200\ shirts\ on\ display$

Part C) Explain what the solution means in the situation

1) Initially on display were the amount of 200 or more shirts

2) 2/5 were sold and 120 or more shirts were left on display.

3) The store brought out another 30 shirts from the stockroom and placed them on display, for a total of 150 shirts or more on display

8 0

3 years ago