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3 years ago

14

Given that cot A = 16/63 and that angle A is in Quadrant I, find the exact value of cscA in simplest radical form using a ration

al denominator.

1 answer:

spin [16.1K]3 years ago

4 0

Answer:

Below in bold.

Step-by-step explanation:

cot = adjacent side / opposite side = 16/63

So the hypotenuse = √(16^2 + 63^2)

= √4225

= 65.

So csc A = hypotenuse /opposite side

= 65/63

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