Answer:
The exact answer in terms of radicals is ![x = 5*\sqrt[3]{25}](https://tex.z-dn.net/?f=x%20%3D%205%2A%5Csqrt%5B3%5D%7B25%7D)
The approximate answer is 
(accurate to 5 decimal places)
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Work Shown:
Let ![y = \sqrt[5]{x^3}](https://tex.z-dn.net/?f=y%20%3D%20%5Csqrt%5B5%5D%7Bx%5E3%7D)
So the equation reduces to -7 = 8-3y
Let's solve for y
-7 = 8-3y
8-3y = -7
-3y = -7-8 ... subtract 8 from both sides
-3y = -15
y = -15/(-3) ... divide both sides by -3
y = 5
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Since and y = 5, this means we can equate the two expressions and solve for x
![\sqrt[5]{x^3} = 5](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bx%5E3%7D%20%3D%205)
Raise both sides to the 5th power
![x = \sqrt[3]{3125}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5B3%5D%7B3125%7D)
Apply cube root to both sides
![x = \sqrt[3]{125*25}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5B3%5D%7B125%2A25%7D)
![x = \sqrt[3]{125}*\sqrt[3]{25}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5B3%5D%7B125%7D%2A%5Csqrt%5B3%5D%7B25%7D)
![x = \sqrt[3]{5^3}*\sqrt[3]{25}](https://tex.z-dn.net/?f=x%20%3D%20%5Csqrt%5B3%5D%7B5%5E3%7D%2A%5Csqrt%5B3%5D%7B25%7D)
Answer:
Option (2)
Step-by-step explanation:
Given question is incomplete; here is the complete question.
Point A is the midpoint of side XZ and point B is the midpoint of side YZ.
Triangle XYZ is cut by line segment AB. Point A is the midpoint of side XZ and point B is the midpoint of side YZ. The length of XY is (5x - 7), the length of AB is (x + 1), and the lengths of XA and ZA are (2x - 2). The lengths of YB and BZ are congruent.
What is AX ?
2 units
4 units
6 units
8 units
From the figure attached,
XYZ is a triangle having A and B as the midpoints of the sides XZ and YZ.
By the theorem of midpoints,
AB = 
Since AB = (x + 1) and XY = (5x - 7)
(x + 1) = 
2x + 2 = 5x - 7
5x - 2x = 2 + 7
3x = 9
x = 3
Therefore, side AB = 3 + 1 = 4 units
Side XY = (5x - 7)
= 15 - 7
= 8 units
Side XA = 2(x - 1)
= 4 units
Therefore, Option (2) will be the answer.
Answer:
option 1 is true. -1/2=-0.5
Eleven times a number X, minus a second number Y
So, The algebraic equation formed with this data is;
<h3>X×11-Y</h3>
Answer:
69 centimeters squared
Step-by-step explanation:
First, find the area of the big square = 11cm * 4cm = 44cm
Next, find the area of the leftover square = 5cm * 5cm =25cm
Add them together to get 69 centimeters squared
Hopefully this helps - let me know if you have any questions!
