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4 years ago

How do you solve this equation?

Mathematics

1 answer:

ANTONII [103]4 years ago

5 0

Answer:

b=85º

a=20º

Step-by-step explanation:

Angle B is supplementary with the 45º and the 50º angle, therefore the sum of the three angles must be 180

45+b+50=180

95+b=180

b=85º

Angle A, Angle B, and the 75º angle must also add up to 180

85+75+a=180

160+a=180

a=20º

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Point P’(5,-4) is the image of point(2,3) under a translation what is the image of 6,-2 under the same translation

Gre4nikov [31]

Answer:

Step-by-step explanation:

(2,3) to (5,-4) its (3,-7) so you jus add (3,-7) to (6,-2) and it gives you (9,-9)

I dont know if it makes sense but yea

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3 years ago

Easy question There are 8 sixth-graders and 16 seventh-graders in a class.

Paha777 [63]

Answer:

2:3

Step-by-step explanation:

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2 years ago

Find the exact values of a) sec of theta b)tan of theta if cos of theta= -4/5 and sin<0

Gre4nikov [31]

Answer:

Using trigonometric ratio:

$\sec \theta = \frac{1}{\cos \theta}$

$\tan \theta = \frac{\sin \theta}{\cos \theta}$

From the given statement:

$\cos \theta = -\frac{4}{5}$ and sin < 0

⇒ $\theta$ lies in the 3rd quadrant.

then;

$\sec \theta = \frac{1}{-\frac{4}{5}} = -\frac{5}{4}$

Using trigonometry identities:

$\sin \theta = \pm \sqrt{1-\cos^2 \theta}$

Substitute the given values we have;

$\sin \theta = \pm\sqrt{1-(\frac{-4}{5})^2 } =\pm\sqrt{1-\frac{16}{25}} =\pm\sqrt{\frac{25-16}{25}} =\pm \sqrt{\frac{9}{25} } = \pm\frac{3}{5}$

Since, sin < 0

⇒ $\sin \theta = -\frac{3}{5}$

now, find $\tan \theta$ :

$\tan \theta = \frac{\sin \theta}{\cos \theta}$

Substitute the given values we have;

$\tan \theta = \frac{-\frac{3}{5} }{-\frac{4}{5} } = \frac{3}{5}\times \frac{5}{4} = \frac{3}{4}$

Therefore, the exact value of:

(a)

$\sec \theta =-\frac{5}{4}$

(b)

$\tan \theta= \frac{3}{4}$

7 0

4 years ago

Please help thank you :)))

lukranit [14]

Answer:

x = 25.46

Step-by-step explanation:

$x^2+9^2=27^2\\x^2+81=729\\x^2=648\\\sqrt{x^2} =\sqrt{648} \\x=25.46$

3 0

3 years ago

A container of water holds 128 fluid ounces. Toya drinks 8 fluid ounces of water every hour. How many fluid ounces are in the co

Sidana [21]

Answer: 64 fluid ounces

Step-by-step explanation:

Amount of water in the container = 128 fluid ounces

Amount drank by Toya every hour = 8 fluid ounces

For 8 hours, Toya would have drank:

= 8 × 8 fluid ounces

= 64 fluid ounces

To calculate the amount of fluid ounces

thataree in the container after 8 hours, we then subtract 64 fluid ounces from 128 fluid ounces. This will be:

= 128 fluid ounces - 64 fluid ounces

= 64 fluid ounces

3 0

3 years ago