1 3 Which is the best estimate of 11. 113 2 4? O 4 O 6 o 22 O 33

Ksivusya [100]

Answer:

Yes, an arrow can be drawn from 10.3 so the relation is a function.

Step-by-step explanation:

Assuming the diagram on the left is the domain(the inputs) and the diagram on the right is the range(the outputs), yes, an arrow can be drawn from 10.3 and the relation will be a function.

The only time something isn't a function is if two different outputs had the same input. However, it's okay for two different inputs to have the same output.

In this problem, 10.3 is an input. If you drew an arrow from 10.3 to one of the values on the right, 10.3 would end up sharing an output with another input. This is allowed, and the relation would be classified as a function.

However, if you drew multiple arrows from 10.3 to different values on the right, then the relation would no longer be a function because 10.3, a single input, would have multiple outputs.

3 0

3 years ago

Find the values of x for which the equation cos x = 1 is true

BlackZzzverrR [31]

Just find the inverse cosine of 1 which is 0 degrees.

3 0

2 years ago

Pls help im failing i need help ASAP

likoan [24]

The answer is choice 1 because when you divide 2 numbers with the same base and different exponents you subtract the second exponent from the first.

p^-m / p^-n = p^(-m - (-n))

CHOICE 1

Hope this helps

7 0

2 years ago

Travel time data is collected on an arterial. With 30 runs, an average travel time of 152 seconds is computed over the 2.0 miles

o-na [289]

Answer:

a

The 95% confidence bounds is $145.80 < \mu < 158.19$

b

It was not necessary to make any assumption about the shape of the travel time distribution

Step-by-step explanation:

From the question we are told that

The sample size is n = 30

The sample mean is $\=x = 152$

The standard deviation is $\sigma = 17.3 \ second$

From the question we are told the confidence level is 95% , hence the level of significance is

$\alpha = (100 - 95 ) \%$

=> $\alpha = 0.05$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{\sigma }{\sqrt{n} }$

=> $E = 1.96 * \frac{17.3 }{\sqrt{30} }$

=> $E = 6.19$

Generally 95% confidence bounds is mathematically represented as

$\= x -E < \mu < \=x +E$

=> $152 -6.19 < \mu < 152 -6.19$

=> $145.80 < \mu < 158.19$

This 95% confidence bounds show that there is 95% confidence that the true mean lies within this bound hence there is it was not necessary to make any assumption about the shape of the travel time distribution

5 0

2 years ago

College Math!!! I did the first half of the question, I just need the bottom half of it.

ella [17]

Answer:

-49

Step-by-step explanation:

$\int _{-5}^{-2}\:\left(8\:w\left(r\right)-3\right)dr$ = $\int _{-5}^{-2}\:8\:w\left(r\right)dr$ -3 (-2 -(-5)) = $8 \int _{-5}^{-2}\:\:w\left(r\right)dr$ -9 =8(-5) -9 = -49

7 0

2 years ago

1 3 Which is the best estimate of 11. 113 2 4? O 4 O 6 o 22 O 33​

1 3 Which is the best estimate of 11. 113 2 4? O 4 O 6 o 22 O 33