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3 years ago

14

Identify the slope and y-intercept. If the equation is in standard form, you may need to switch it to slope-intercept form. Sket

ch the graph of each line.
4x + 3y = -9

1 answer:

trasher [3.6K]3 years ago

6 0

Vertical intercept: (0, -3)

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Solve the system of equations algebraically.

andrew11 [14]

Answer: d. (17, 20)

Step-by-step explanation:

We have the following system of equations:

$x-3y=8$ (1)

$5x-4y=5$ (2)

Isolating $x$ from (1):

$x=\frac{8+3y}{4}$ (3)

Substituting (3) in (2):

$5(\frac{8+3y}{4})-4y=5$ (4)

Isolating $y$ :

$\frac{40}{4}+\frac{15 y}{4}-4y=5$ (5)

$10-5=4y-\frac{15 y}{4}$ (6)

$y=20$ (7)

Substituting (7) in (1):

$x-3(20)=8$ (8)

Isolating $x$ :

$x=17$ (9)

Hence, the correct option is d. (17, 20)

8 0

3 years ago

Solve for x<br> 4(x + 1) = –28

lora16 [44]

Answer:

X=-8

Step-by-step explanation:

4x+4=-32

Add -4 to both sides

4x=-32

decide both sides by 4

x=-8

4 0

3 years ago

8-1 1/5<br> (Simplify your answer. Type a whole number, fraction, or a mixed number.)<br> orrect:

ozzi

The answer is 6 4/5!

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4 years ago

Read 2 more answers

Tony works 22 hours per week. His take home pay is $15.80 per hour. If Tony is able to save all of his earnings, how long will i

denis23 [38]

About 14 weeks to reach 4800

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3 years ago

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Q6: Which is the graph of the polar equation r=1/1-sin theta.

AveGali [126]

Answer:

The correct answer is C.

Step-by-step explanation:

The given equation is;

$r=\frac{1}{1-\sin(\theta)}$

This implies that;

$r(1-\sin(\theta)=1$

$r-r\sin(\theta)=1$

Let us write in Cartesian coordinates by substituting;

$r=\sqrt{x^2+y^2} ,y=r\sin(\theta)$

$\sqrt{x^2+y^2}-y=1$

$\sqrt{x^2+y^2}=y+1$

Square both sides;

$(\sqrt{x^2+y^2})^2=(y+1)^2$

This implies that;

$x^2+y^2=y^2+2y+1$

$x^2=2y+1$

$y=\frac{1}{2}x^2-\frac{1}{2}$

This is an equation of a parabola that opens upwards with a y-intercept of $-\frac{1}{2}$ .

The correct choice is C

4 0

4 years ago