We know that
∠ TSR = 84°
if SQ bisects ∠ <span>TSR
then
</span>∠ RSQ = ∠ TSR/2
<span>so
</span>∠ RSQ = (1/2)*84°----- 42°
∠ RSQ = 3x-9
3x-9=42-------> 3x=42+9------> 3x=51-----> x=51/3-----> x=17°
<span>
the answer is
</span>x=17°<span>
</span>
Answer:
-15a+d
Step-by-step explanation:
5a-20a+12d-11d
-15a+d
5z>15-----subtract 2 on both sides
z>3----divide by 5
therefore, z must equal -10, or -4
Answer:
uh what is this address for or am i not supposed to be in this
Step-by-step explanation:
sorry if im getting in your buisness
