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max2010maxim [7]
4 years ago
9

What is the numerical expression 5/8 - 5/12 (3-1/4) + 2/3 A.9 B.2 C.1/2 D.1/9

Mathematics
1 answer:
Ronch [10]4 years ago
8 0
The answer is B. 7/48
Hope this helps!
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Find the sum: (3x2 + 5x − 8) + (5x2 − 13x − 5)
musickatia [10]

Answer:

(3x^2+5x-8)+(5x^2-13x-5)=8x^2-8x-13

Step-by-step explanation:

The given polynomials are,

3x^2+5x-8,5x^2-13x-5

In polynomial addition and subtraction only like terms can be added or subtracted.

So,

=(3x^2+5x-8)+(5x^2-13x-5)

=3x^2+5x-8+5x^2-13x-5

=3x^2+5x^2+5x-13x-8-5

=8x^2-8x-13

7 0
3 years ago
Read 2 more answers
Solve and graph the absolute value inequality: |2x + 4| > 8​
neonofarm [45]

Answer:

C

Step-by-step explanation:

To get rid of the absolute value bars you have to get two different equations which would be 2x+4>-8 AND 2x+4>8. Pay attention to the signs, if there is greater than or equal to then it would have a line underneath the sign, which neither of the equations should have since you haven't moved a negative. solve normally and you'll get -6 blank circle and 2 blank circle.

4 0
3 years ago
Find two consecutive odd integers whose product is 323
Harrizon [31]
Use a let statement 
first
let x and x + 2 be the number so you write it like this
<u>let x = the first consecutive integer
</u><u>let x + 2 = the second consecutive integer
</u>
second
x(x+2)=323
x^2 + 2x = 323
        -323  -323
x^2 + 2x -323 = 0

third
try to factor -323 so it is 19 and -17
(x + 19) (x - 17) = 0
x = 19 
x = -17

hope this help

4 0
3 years ago
Suppose<br> cos(π/2−x) =3/5, cos x =4/5<br> find sin, tan, csc, sec, cot
Pani-rosa [81]
Cos (π/2 - x) = sin x = 3/5
tan x = sin x / cos x = 3/5 / 4/5 = 3/4
csc x = 1/sin x = 1 / 3/5 = 5/3
sec x = 1/cos x = 1 / 4/5 = 5/4
cot x = 1/tan x = 1 / 3/4 = 4/3.
5 0
3 years ago
Porphyrin is a pigment in blood protoplasm and other body fluids that is significant in body energy and storage. Let x be a rand
SOVA2 [1]

Answer:

<u>Question 1:</u>

<u>(a) </u>P(x<60) = 0.9236

<u>(b) </u>P(x>16) = 0.9564

<u>(c) </u>P(16<x<60) = 0.88

<u>(d) </u>P (x>60) = 0.0764

<u />

<u>Question 2:</u>

<u>(a) </u>P(x<3) = 0.0668

<u>(b) </u>P(x>7) = 0.0062

<u>(c) </u>P(3<x<7) = 0.927

<u />

Step-by-step explanation:

<u>Question 1:</u>

x = no. of mg of porphyrin per deciliter of blood.

μ = 40

σ = 14

(a) We need to compute P(x<60). We need to find the z-score using the normal distribution formula:

z = (x - μ)/σ

P(x<60) = P((x - μ)/σ < (60 - 40)/14)

             = P(z < 20/14)

             = P(z<1.43)

Using the normal distribution probability table we can find the value of p at z=1.43.

P(z<1.43) = 0.9236

so, P(x<60) = 0.9236

(b) P(x>16) = P(z>(16-40)/14)

                 = P(z>-1.71)

                 = 1 - P(z<-1.71)

                 = 1 - 0.0436

    P(x>16) = 0.9564

(c) P(16<x<60) = P((16-40)/14) < x < (60-40)/14)

                        = P(-1.71 < z < 1.43)

This probability can be calculated as: P(z<1.43) - P(z<-1.71)

                                         P(16<x<60) = 0.9236 - 0.0436

                                         P(16<x<60) = 0.88

(d) P(x>60) = 1 - P(x<60)

     we have calculated P(x<60) in part (a) so,

    P(x>60) = 1 - 0.9236

    P (x>60) = 0.0764

<u>Question 2:</u>                              

μ = 4.5 mm

σ = 1.0 mm

In this question, we will again compute the z-scores and then find the probability from the normal distribution table.

(a) P(x<3) = P(z<(3-4.5)/1)

                = P(z<-1.5)

     P(x<3) = 0.0668

(b) P(x>7) = 1 - P(x<7)

               = 1 - P(z<(7-4.5)/1)

               = 1 - P(z<2.5)

               = 1 - 0.9938

    P(x>7) = 0.0062

(c) P(3<x<7) = P(x<7) - P(x<3)

  we have computed both of these probabilities in parts (a) and (b) so,

    P(3<x<7) = 0.9938 - 0.0668

    P(3<x<7) = 0.927

6 0
3 years ago
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