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max2010maxim [7]
3 years ago
9

What is the numerical expression 5/8 - 5/12 (3-1/4) + 2/3 A.9 B.2 C.1/2 D.1/9

Mathematics
1 answer:
Ronch [10]3 years ago
8 0
The answer is B. 7/48
Hope this helps!
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A video club wants to reward its best members with a discount based on the member’s number of movie rentals and the number of ne
ivanzaharov [21]

Answer:

public class MovieRental

{

public static void main(String[] args)

{

 Scanner in = new Scanner(System.in);

 

 System.out.print("Enter the number of movie rentals: ");

 int movieRentals = in.nextInt();

 

 System.out.print("Enter the number of members referred to the video club: ");

 int memberReferral = in.nextInt();

 

 in.close();

 

 double discountVal = Math.min(movieRentals + memberReferral, 75);

 

 System.out.println("The discount is equal to: " + discountVal);

}

}

8 0
3 years ago
The area of a rectangle is greater than or equal to 115 square cm. The width of the rectangle is 5 cm and the Length of the rect
sattari [20]
Area= length*width
115= x * 5
115/5 = x
23 = x
So the length will be 23 cm.
4 0
3 years ago
Help me plzzzz<br> I need to turn this in plz help me
cupoosta [38]

Answer:

75 miles

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
A $1,000.00 bond at 85 1/4 % pays 6.8 % annual interest. Calculate cost of bond.
stepladder [879]

Based on the par value of the bond and the percentage it was issued at, the cost of the bond is $852.50.

<h3>What is the cost of the bond?</h3>

The current cost of the bond is the present value of the bond's cashflows and its par value.

This is taken into account when the bond is issued at a certain percentage which in this case is 85 ¹/₄%.

The cost of the bond is:

= 1,000 x 85 ¹/₄%

= $852.50

Find out more on the cost of bonds at brainly.com/question/15567868.

#SPJ1

8 0
2 years ago
Hi, can someone help me on this. I'm stuck --
CaHeK987 [17]

Answer:

a) Fx=-5N  Fy=-5*sqrt(3) N   b) Fx= 5*sqrt(3) N    Fy=-5N

c) Fx=-5*sqrt(2) N    Fy=-5*sqrt(2)   N

Step-by-step explanation:

The arrow's F ( weight) component on axle x  is Fx= F*sinA  and on axle y is

Fy=F*cosA

a) The x component and y component both are opposite directed to axle x and axle y accordingly.  So both components are negative.

So Fx = - 10*sin(30)= -5 N      Fy= -10*cos(30)= -10*sqrt(3)/2= -5*sqrt (3) N

b) Now the x component  is co directed to axle x , and y component is opposite directed to axle y.

So x component is positive and y components is negative

So Fx = 10*sin(60)= 5*sqrt(3) N       Fy= -10*cos(60)= -10*1/2= -5 N

c)The x component and y component both are opposite directed to axle x and axle y accordingly.  So both components are negative.

So Fx = - 10*sin(45)= -5*sqrt(2)  N    

 Fy= -10*cos(45)= -10*sqrt(2)/2= -5*sqrt (2) N

8 0
3 years ago
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