The equation that best describes the situation is A. 1,500 + 690h = 2,500
<h3 /><h3>Speed of plane after tailwind</h3>
Since the plane has already covered 1500 miles, and the plane travelling at 450 knots in still air picks up at tailwind of 150 knots in the same direction, the resultant velocity, V of the plane = speed of plane in still air + speed of wind
= 450 knots + 150 knots
= 600 knots
= 600 × 1 knot
= 600 × 1.15 mph
= 690 mph.
<h3 /><h3>Distance of plane after tailwind</h3>
If h is the number of hours after picking up the tail wind, the distance moved by the airplane is thus D = 1500 + 690h
<h3 /><h3>Required equation</h3>
Since D = 2500 miles, we have
1500 + 690h = 2500.
So, the equation that best describes the situation is A. 1,500 + 690h = 2,500
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