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Aleonysh [2.5K]
3 years ago
11

Find the slope of the following ordered pairs. (1, -3/4 ) and (4, -3)

Mathematics
2 answers:
puteri [66]3 years ago
8 0
M= -3/4
Hope this helps
prohojiy [21]3 years ago
7 0

Answer: -3/4

Step-by-step explanation:Use the slope formula to find the slope  

m

.

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I need help with this please (sorry it’s upside down)
Ganezh [65]

1.) 1.67×10 to the power of 9

2.) 1.133×10 to the power of -3

3.) 1.75×10 to the power of 9

4.) 2.64×10 to the power of 4

5.) 2.947×10 to the power of -6

6.) 4.24×10 to the power of 5

7.) 1.0207×10 to the power of 6

8.) 1.027×10 to the power of 5

5 0
3 years ago
The participants in a research study self-report their sleep quality levels by choosing the response option that best characteri
Bad White [126]

Answer:

This is a Categorical variable and the measurement scale is ordinal scale.

Step-by-step explanation:

The measurement scale that is being used to classify sleep is the ordinal measurement. In this question, the variable that is called sleep quality is a categorical variable. categorical variables are variables that have the data representing groups. sleep quality has been given this categorical order extremely low very low low and extreme high.

The ordinal scale is a scale that denotes order it has all variables in a specific order.

6 0
3 years ago
Antibiotics in Infancy
leonid [27]

Answer:

e)The information from the sample does not give enough information  to support that more than 70% of Canadian children receive antibiotics during the first year of life

Step-by-step explanation:

The proportion we will use for the test is  p  = 70 %

From a random sample we got

n  =  616

x = 438      then   p₁ = 438/616     p₁  =  0,71    p₁  = 71 %

Then  q₁  =  1 - p₁      q₁  = 1 - 0,71    q₁ = 0,29   q₁ = 29 %

a) Hypothesis test:

Null hypothesis                      H₀           p₁   = p

Alternative hypothesis          Hₐ           p₁  > p >70 %

CI = 95 % significance level    α  = 5 %   α = 0,05

z(c) for  α  =  0,05   from z-table is    z(c)  = 1,64

b) To calculate  z(s)  =  ( p₁  -  p ) / √ p₁*q₁ / n

z(s) = ( 0,71  -  0,70 )/ √ 0,71*0,29/616

z(s) = 0,01 /0,01828

z(s) = 0,547 ≈ 0,55

c) p-value for   z(s) is from z-table   p-value ≈ 0,7088

d) p-value > 0,05   then we accept H₀  we don´t have enough evidence to reject H₀

e)The information from the sample does not give enough information  to support that more than 70% of Canadian children receive antibiotics during the first year of life

3 0
3 years ago
Round off the following numbers to the nearest thousand. 19. 674,620 20. 355,500
Oksana_A [137]

Answer:

1) 675,000.

2) 356,000

Step-by-step explanation:

There are some rules to round off to the nearest thousand.

1. While rounding off to the nearest thousand, if the digit in the hundreds place is between 0 – 4 i.e., < 5, then the hundreds place is replaced by ‘0’.

2. If the digit in the hundreds place is = to or > 5, then the hundreds place is replaced by ‘0’ and the thousands place is increased by 1.

We have given two numerals:

1)<u> 674,620</u>

According to the second rule defined the digit at the hundreds place is greater than 5 than the thousands place will be increased by 1.

The answer is 675,000.

2) <u>355,500</u>

According to the second rule defined the digit at the hundreds place is greater than 5 than the thousands place will be increased by 1.

The answer is 356,000....

4 0
3 years ago
Explain why a quadratic equation with a positive discriminant has two real solutions, a quadratic equation with a negative discr
Bad White [126]

Answer:

A quadratic equation can be written as:

a*x^2 + b*x + c = 0.

where a, b and c are real numbers.

The solutions of this equation can be found by the equation:

x = \frac{-b +- \sqrt{b^2 - 4*a*c} }{2*a}

Where the determinant is D = b^2 - 4*a*c.

Now, if D>0

we have the square root of a positive number, which will be equal to a real number.

√D = R

then the solutions are:

x = \frac{-b +- R }{2*a}

Where each sign of R is a different solution for the equation.

If D< 0, we have the square root of a negative number, then we have a complex component:

√D = i*R

x = \frac{-b +- C*i }{2*a}

We have two complex solutions.

If D = 0

√0 = 0

then:

x = \frac{-b +- 0}{2*a} = \frac{-b}{2a}

We have only one real solution (or two equal solutions, depending on how you see it)

3 0
3 years ago
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