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Gala2k [10]
3 years ago
6

Antibiotics in Infancy

Mathematics
1 answer:
leonid [27]3 years ago
3 0

Answer:

e)The information from the sample does not give enough information  to support that more than 70% of Canadian children receive antibiotics during the first year of life

Step-by-step explanation:

The proportion we will use for the test is  p  = 70 %

From a random sample we got

n  =  616

x = 438      then   p₁ = 438/616     p₁  =  0,71    p₁  = 71 %

Then  q₁  =  1 - p₁      q₁  = 1 - 0,71    q₁ = 0,29   q₁ = 29 %

a) Hypothesis test:

Null hypothesis                      H₀           p₁   = p

Alternative hypothesis          Hₐ           p₁  > p >70 %

CI = 95 % significance level    α  = 5 %   α = 0,05

z(c) for  α  =  0,05   from z-table is    z(c)  = 1,64

b) To calculate  z(s)  =  ( p₁  -  p ) / √ p₁*q₁ / n

z(s) = ( 0,71  -  0,70 )/ √ 0,71*0,29/616

z(s) = 0,01 /0,01828

z(s) = 0,547 ≈ 0,55

c) p-value for   z(s) is from z-table   p-value ≈ 0,7088

d) p-value > 0,05   then we accept H₀  we don´t have enough evidence to reject H₀

e)The information from the sample does not give enough information  to support that more than 70% of Canadian children receive antibiotics during the first year of life

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