The square (call it ) has one vertex at the origin (0, 0, 0) and one edge on the y-axis, which tells us another vertex is (0, 3, 0). The normal vector to the plane is , which is enough information to figure out the equation of the plane containing :
We can parameterize this surface by
for and . Then the flux of , assumed to be
,
is
Answer:
≥
Step-by-step explanation:
Yes you do need to regroup it would be 4
Answer:
just multiply 239 * 45 in a paper you will get the answer
if you can't I will edit answer and show
Answer:
3x-4y=15
7x+y=4
Solve7x+y=4 for y:
7x+y=4
7x+y+−7x=4+−7x (Add -7x to both sides)
y=−7x+4
Step: Substitute −7x+4 for y in 3x−4y=15:
3x−4y=15
3x−4(−7x+4)=15
31x−16=15 (Simplify both sides of the equation)
31x−16+16=15+16 (Add 16 to both sides)
31x=31
(Divide both sides by 31)
x=1
Step: Substitute 1 for x in y=−7x+4:
y=−7x+4
y=(−7)(1)+4
y=−3(Simplify both sides of the equation)
Answer: x=1 and y=−3