4) You know slope-intercept form is y=mx+b. So using these two given points, you can find the slope!
(-8,5) (-3,10) [Use the y1-y2 over x1-x2 formula to solve for slope]
10 - 5 5 --------- = ----- = 1 -3-(-8) 5
Hurray! You got a slope of one. Now substitute this back into your original equation: y=mx+b --> y=1x+b
Next, we find what our "b" is, or what our y-intercept is: Using one of the previous points given, substitute them into the new equation: [I used the point (-3, 10) ]
So, now we have our y-intercept. Use this and plug it into the equation: y=1x+b --> y=1x+13
y=1x+13 is our final answer.
5) So for perpendicular lines, your slope will be the opposite reciprocal of the original slope. (Ex: Slope is 2, but perpendicular slope is -1/2)
We have the equation y= 3x-1, so find the reciprocal slope! --> y=-1/3x-1
Good! Now we take our given point, (9, -4) and plug it into the new equation:
y=-1/3x-1 -4=-1/3(9)+b SUBSTITUTE and revert "-1" to "b", for we are trying to find the y- -4=-3+b intercept of our perpendicular equation. +3 +3 ADD -------- -1=b SIMPLIFY
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