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natta225 [31]
3 years ago
12

What is the equation of the additive relationship represented by this table.

Mathematics
2 answers:
DerKrebs [107]3 years ago
6 0

Answer:

sorry I did not mean to answer this i accidentaly clicked this. 0.0 i hope you don't get mad :(

Step-by-step explanation:

fredd [130]3 years ago
4 0
Your answer is y=x+2 because 2+2 is 4 and 4+2 is 6 so 2 is your rate of change
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Steven has 24 t-shirts. One third of the t-shirts are white, one fourth of the t-shirts are blue ; the remainder of the t-shirts
Black_prince [1.1K]
White t-shirts = 8, blue t-shirts =6 6+8=14 24-14=10 orange tshirts
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3 years ago
Please help me with this math
natulia [17]

The slope is -1/2 or -0.5

3 0
2 years ago
What is the measure of LXZW?<br> 850<br> 150°<br> Y<br> 65°<br> 95<br> Z<br> 215°<br> W<br> 30°
Semenov [28]

Answer:

so the answer is 95°

Step-by-step explanation:

The two angles on a line add up to 180° or are supplementary, so we can find the inside angle x by doing 180-150=30°. Now that we know inside x is 30, if we add 30+65, we get 95, and 180-95=85°. Then to find angle xzw, just do 180-85 to get 95°.

3 0
3 years ago
What is 39.5% written as a fraction in simplest forma?
ivann1987 [24]
First covert 39.5% to a decimal to get 0.395.
0.395 written as a fraction is \frac{395}{1000}
Simplify \frac{395}{1000} to get \frac{79}{200}
6 0
4 years ago
. Let X and Y be random variables of possible percent returns (0%, 10%,
bazaltina [42]

(a) The marginal distribution of <em>X</em> is

Pr(<em>X</em> = <em>x</em>) = ∑ Pr(<em>X</em> = <em>x</em>, <em>Y</em> = <em>y</em>)

… = 0.0625 + 0.0625 + 0.0625 + 0.0625

… = 0.25

That is, the first equality follows from the law of total probability, with the sum taken over <em>y</em> from {0, 5, 10, 15}. Each probability Pr(<em>X</em> = <em>x</em>, <em>Y</em> = <em>y</em>) is given in the table to be 0.0625.

Similarly, the marginal distribution of <em>Y</em> is

Pr(<em>Y</em> = <em>y</em>) = 0.25

(b) Yes, they're independent because

Pr(<em>X</em> = <em>x</em>, <em>Y</em> = <em>y</em>) = 0.0625,

and

Pr(<em>X</em> = <em>x</em>) Pr(<em>Y</em> = <em>y</em>) = 0.25 • 0.25 = 0.0625.

(c) The mean of <em>X</em> is

E[<em>X</em>] = ∑ <em>x</em> Pr(<em>X</em> = <em>x</em>)

… = 0.25 ∑ <em>x</em>

<em>… </em>= 0.25 (0 + 5 + 10 + 15)

… = 7.5

and you would find the same mean for <em>Y</em>,

E[<em>Y</em>] = 7.5

The variance of <em>X</em> is

V[<em>X</em>] = E[<em>X</em>^2] - E[<em>X</em>]^2

… = (∑ <em>x</em>^2 Pr(<em>X</em> = <em>x</em>)) - 7.5^2

… = 0.25 (∑ <em>x</em>^2) - 56.25

… = 0.25 (0^2 + 5^2 + 10^2 + 15^2) - 56.25

… = 31.25

and similarly,

V[<em>Y</em>] = 31.25

(each sum is taken with <em>x</em> and <em>y</em> from {0, 5, 10, 15})

7 0
3 years ago
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