Y = -3x + 6....the slope here is -3. A parallel line will have the same slope.
y = mx + b
slope(m) = -3
(-4,7)....x = -4 and y = 7
now we sub into the formula and find b, the y int
7 = -3(-4) + b
7 = 12 + b
7 - 12 = b
-5 = b
so ur parallel equation is : y = -3x - 5 <==
Answer:
Domain: {-1,-2,-3,-4}
Range: {4,5}
Step-by-step explanation:
As the range has repeated numbers, you don't have to repeat them.
The smallest region that can be photographed is
5*7 = 35 square km
so we want to know how long it takes to zoom out to an area of
35 * 5 = 175 square km.
Notice that the length and width increase at the same rate, 2 km/sec, and they start out with a difference of two, so when the width has increased from 5 to x, the length will have increased from 7 to x+2. At the desired coverage area, then,
x(x+2) = 175
x^2 + 2x = 175
x^2 + 2x + 1 = 176 [completing the square]
(x+1)^2 = 176
x+1 = ±4√11
x = -1 ±4√11
Since a negative value for x is meaningless here, x must be
-1 + 4√11 = about 12.27 km
and the time it took to increast to that value was
(12.27 - 5) km / (2 km/sec) = about 3.63 seconds
