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saveliy_v [14]
3 years ago
5

A baby gains 11 pounds in it’s first year of life.The baby gained 4 1/4 pounds during the first four months and 3 1/2 pounds in

its second four months. How much did the baby gain in the last four months?
3 1/4 pounds
3 1/2 pounds
4 pounds
5 pounds
Mathematics
1 answer:
Olin [163]3 years ago
5 0

Step-by-step explanation:

Do 4 1/4+ 3 1/3= 7 3/4

11- 7 3/4= 3 1/4

Hope this helped. Thank me later.

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Answer:

he studies his math for 15 hours

Step-by-step explanation:

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WILL MARK U AS BRAINLIEST SHOW WORK SOLVE BY ELIMINATION-3x+y=-18<br> -3x+y=-6
Sindrei [870]
No solution exists for -3x+y=-18 and -3x+y=-6
8 0
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What set of lengths forms a right triangle?
Leni [432]
The answer is C. 50 in, 48 in, 14 in

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3 years ago
A sales representative from a local radio station is trying to convince the owner of a small fitness club to advertise on her st
Otrada [13]

Answer:

  C.  the initial number of club members, in hundreds

Step-by-step explanation:

The general form of such an expression is ...

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_____

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  1.8(1.02^(12t))

8 0
3 years ago
Need help with this....
Yakvenalex [24]

Answer:

\boxed{\dfrac{f(a+h)-f(a)}{h}=-3a^2-3ah-h^2}

Step-by-step explanation:

f(x)=-x^3+2\\\\\dfrac{f(a+h)-f(a)}{h}\\\\f(a+h)\to\text{substitute x = a + h}\\f(a)\to\text{substitute x = a}\\\\\dfrac{f(a+h)-f(a)}{h}=\dfrac{-(a+h)^3+2-(-a^3+2)}{h}\\\\\text{use}\ (x+y)^3=x^3+3x^2y+3xy^2+y^3\\\\=\dfrac{-(a^3+3a^2h+3ah^2+h^3)+2-(-a^3)-2}{h}\\\\=\dfrac{-a^3-3a^2h-3ah^2-h^3+2+a^3-2}{h}\\\\\text{combine like terms}

=\dfrac{(-a^3+a^3)-3a^2h-3ah^2-h^3+(2-2)}{h}\\\\=\dfrac{-3a^2h-3ah^2-h^3}{h}\\\\=\dfrac{h(-3a^2-3ah-h^2)}{h}\\\\=-3a^2-3ah-h^2

6 0
3 years ago
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