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olasank [31]
3 years ago
7

This graph shows a proportional relationship.

Mathematics
2 answers:
xxMikexx [17]3 years ago
4 0

Step-by-step explanation:

what u suppose to do on this work, reply quickly so I can help

Bond [772]3 years ago
3 0

Answer:

help

Step-by-step explanation:

help

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To find the height of a pole, a surveyor moves 150 feet away from the base of the pole and then, with a transit 4 feet tall, mea
ladessa [460]

Answer: The answer is 139 feet

H = height of the pole =?

BC = ED = height of the transit = 4 ft

CD = BE = distance moved away from the base of the pole = 140 ft

Consider the ΔABE

tan44 = AE/BE

tan44 = h/140

h = 140 tan44

h = 135.2 ft

H = height of pole = AE + ED = h + ED = 135.2 + 4

H = 139.2 ft

Step-by-step explanation:

6 0
2 years ago
1. find the balance after one year if you deposit all the money into an account that pays $2.50 in simple interest each month (t
Naddika [18.5K]

1. Balance after 1 year with simple interest= 600 + (2.5 x 12) = 600 + 30 = $630

2. Balance after 1 year with compounded interest = P ( 1 + \frac{r}{n})^{nt}

= 600 ( 1 + \frac{0.05}{12})^{12}= 600 (1.0511) = $630.66 = approx. $630

6 0
4 years ago
Please help I will give points
iVinArrow [24]

Answer:

1/32

Step-by-step explanation:

...

8 0
3 years ago
What are three algebra equations whose solution is x=3 ??
noname [10]

Answer:

2x=6

2x+1=7

2x-1=5

3 0
3 years ago
Read 2 more answers
The heights of a random sample of 50 college students showed a mean of 174.5 centimeters and a standard deviation of 6.9 centime
Minchanka [31]

Answer:

Step-by-step explanation:

Hello!

For me, the first step to any statistics exercise is to determine what is the variable of interest and it's distribution.

In this example the variable is:

X: height of a college student. (cm)

There is no information about the variable distribution. To estimate the population mean you need a variable with at least a normal distribution since the mean is a parameter of it.

The option you have is to apply the Central Limit Theorem.

The central limit theorem states that if you have a population with probability function f(X;μ,δ²) from which a random sample of size n is selected. Then the distribution of the sample mean tends to the normal distribution with mean μ and variance δ²/n when the sample size tends to infinity.

As a rule, a sample of size greater than or equal to 30 is considered sufficient to apply the theorem and use the approximation.

The sample size in this exercise is n=50 so we can apply the theorem and approximate the distribution of the sample mean to normal:

X[bar]~~N(μ;σ2/n)

Thanks to this approximation you can use an approximation of the standard normal to calculate the confidence interval:

98% CI

1 - α: 0.98

⇒α: 0.02

α/2: 0.01

Z_{1-\alpha /2}= Z_{1-0.01}= Z_{0.99} =2.334

X[bar] ± Z_{1-\alpha /2} * \frac{S}{\sqrt{n} }

174.5 ± 2.334* \frac{6.9}{\sqrt{50} }

[172.22; 176.78]

With a confidence level of 98%, you'd expect that the true average height of college students will be contained in the interval [172.22; 176.78].

I hope it helps!

4 0
3 years ago
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