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olasank [31]
2 years ago
7

This graph shows a proportional relationship.

Mathematics
2 answers:
xxMikexx [17]2 years ago
4 0

Step-by-step explanation:

what u suppose to do on this work, reply quickly so I can help

Bond [772]2 years ago
3 0

Answer:

help

Step-by-step explanation:

help

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what differences can be found when contrasting the mood of third person acc with that of claudettes first person account?​
Solnce55 [7]

Answer: The mood of the third-person account is less emotional and more matter-of-fact. The mood of Claudette's account is less emotional and more matter-of-fact.

Step-by-step explanation:

6 0
3 years ago
⚠️6TH GRADE MATH PLEASE HELP I WILL MARK CROWN⚠️
zaharov [31]

Answer:

0.40d

d - 0.60d

Step-by-step explanation:

d - 0.60

This doesn't work because it wants 60<em><u>%</u></em> 0.60 without the percent is a decimal number, and is not 60% of d.

100% - 60% = 40%

0.40d works because it is multiplying 0.40 and d which is also 40%.

d - 0.60d works because it is multiplying 0.60 and d which is also 60% and then subtract it from d.

0.60d doesn't work because it want the discounted price not the discount.

1 - 0.60d doesn't work because we don't know that d = 1, so it is subtracting the discount from 1 not d.

4 0
3 years ago
Which is an equation of the line that passes through the point (8,7) and is perpendicular to the line whose equation is y = 4x-1
algol [13]

Answer:

Y = -1/4x + 5

Step-by-step explanation:

7 0
2 years ago
Find the sum of 160,-125, and 40.
djyliett [7]

The answer is;

160 + (-125) + 40 = 75

<u>75</u>

7 0
3 years ago
Read 2 more answers
How many solutions does the equation |x + 6| − 4 = c have if c = 5? If c = −10? Complete the explanation
mixer [17]

Answer:

<h2>For c = 5 → two solutions</h2><h2>For c = -10 → no solutions</h2>

Step-by-step explanation:

We know

|a|\geq0

for any real value of <em>a</em>.

|a| = b > 0 -  <em>two solutions: </em>a = b or a = -b

|a| = 0 - <em>one solution: a = 0</em>

|a| = b < 0 - <em>no solution</em>

<em />

|x + 6| - 4 = c

for c = 5:

|x + 6| - 4 = 5           <em>add 4 to both sides</em>

|x + 6| = 9 > 0   <em>TWO SOLUTIONS</em>

for c = -10

|x + 6| - 4 = -10           <em>add 4 to both sides</em>

|x + 6| = -6 < 0   <em>NO SOLUTIONS</em>

<em></em>

Calculate the solutions for c = 5:

|x + 6| = 9 ⇔ x + 6 = 9 or x + 6 = -9         <em>subtract 6 from both sides</em>

x = 3 or x = -15

5 0
3 years ago
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