The answer is 14.58.
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For three fair six-sided dice, the possible sum of the faces rolled can be any digit from 3 to 18.
For instance the minimum sum occurs when all three dices shows 1 (i.e. 1 + 1 + 1 = 3) and the maximum sum occurs when all three dces shows 6 (i.e. 6 + 6 + 6 = 18).
Thus, there are 16 possible sums when three six-sided dice are rolled.
Therefore, from the pigeonhole principle, <span>the minimum number of times you must throw three fair six-sided dice to ensure that the same sum is rolled twice is 16 + 1 = 17 times.
The pigeonhole principle states that </span><span>if n items are put into m containers, with n > m > 0, then at least one container must contain more than one item.
That is for our case, given that there are 16 possible sums when three six-sided dice is rolled, for there to be two same sums, the number of sums will be greater than 16 and the minimum number greater than 16 is 17.
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To expand a polynomial, multiply its factors by using the distributive property and then combine all like terms.
<h3>How to illustrate the information?</h3>
It should be noted that a polynomial is an expression which is composed of variables, constants and exponents, which are combined using the mathematical operations such as addition, subtraction, multiplication and division
A polynomial is expanded if there's no variable appears within parentheses and all like terms have been combined.
To expand a polynomial, multiply its factors by using the distributive property or perform the indicated operations. Then combine all like terms.
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