All categories

3 years ago

Rearrange the following formula to make c the subject. a= b/c + 5

Mathematics

1 answer:

zloy xaker [14]3 years ago

5 0

Responder

cachemirisufyan

Experto

168 respuestas

1.5K personas ayudaron

2a + 2c = 5a - 5b

recopilar términos ligeros.

toma 2a en el otro lado

2c = 5a -2a-5b

2c = 3a - 5b

divide 2c's 2 en ambos lados

c = (3a - 5b) / 2

dar un más inteligente por favor. tnx que tengas un buen día.

You might be interested in

Is problem 21 right?

Pepsi [2]

Yes, the answers correct

5 0

3 years ago

What is a pre-image?

KIM [24]

Answer:

an image before the image your seeing

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Use Lagrange multipliers to find the maximum and minimum values of (i) f(x,y)-81x^2+y^2 subject to the constraint 4x^2+y^2=9. (i

sp2606 [1]

i. The Lagrangian is

$L(x,y,\lambda)=81x^2+y^2+\lambda(4x^2+y^2-9)$

with critical points whenever

$L_x=162x+8\lambda x=0\implies2x(81+4\lambda)=0\implies x=0\text{ or }\lambda=-\dfrac{81}4$

$L_y=2y+2\lambda y=0\implies2y(1+\lambda)=0\implies y=0\text{ or }\lambda=-1$

$L_\lambda=4x^2+y^2-9=0$

If $x=0$ , then $L_\lambda=0\implies y=\pm3$ .
If $y=0$ , then $L_\lambda=0\implies x=\pm\dfrac32$ .
Either value of $\lambda$ found above requires that either $x=0$ or $y=0$ , so we get the same critical points as in the previous two cases.

We have $f(0,-3)=9$ , $f(0,3)=9$ , $f\left(-\dfrac32,0\right)=\dfrac{729}4=182.25$ , and $f\left(\dfrac32,0\right)=\dfrac{729}4$ , so $f$ has a minimum value of 9 and a maximum value of 182.25.

ii. The Lagrangian is

$L(x,y,z,\lambda)=y^2-10z+\lambda(x^2+y^2+z^2-36)$

with critical points whenever

$L_x=2\lambda x=0\implies x=0$ (because we assume $\lambda\neq0$ )

$L_y=2y+2\lambda y=0\implies 2y(1+\lambda)=0\implies y=0\text{ or }\lambda=-1$

$L_z=-10+2\lambda z=0\implies z=\dfrac5\lambda$

$L_\lambda=x^2+y^2+z^2-36=0$

If $x=y=0$ , then $L_\lambda=0\implies z=\pm6$ .
If $\lambda=-1$ , then $z=-5$ , and with $x=0$ we have $L_\lambda=0\implies y=\pm\sqrt{11}$ .

We have $f(0,0,-6)=60$ , $f(0,0,6)=-60$ , $f(0,-\sqrt{11},-5)=61$ , and $f(0,\sqrt{11},-5)=61$ . So $f$ has a maximum value of 61 and a minimum value of -60.

5 0

3 years ago

For any whole number b that is a PERFECT SQUARE

photoshop1234 [79]

Is there a diagram? ........

3 0

3 years ago

Read 2 more answers

What are the intercepts of the line 2x + 4y = 12?

Triss [41]

For x-intercepts, you plug 0 for y and solve for x, and vice versa for y-intercepts.

X: 2X+4(0)= 12
2x= 12
12/2= 6 so the x intercept is 6.

Y: 2(0)+4Y=12
4y= 12
12/4= 3 so the y intercept is 3.

Your answer is B. <span>x-intercept: 6; y-intercept: 3</span>

8 0

3 years ago

Read 2 more answers