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Korvikt [17]
3 years ago
12

Divide 64.5 by 0.015, leaving the answer in standard form​

Mathematics
1 answer:
kkurt [141]3 years ago
3 0

Answer:

4.3 *10^3

Step-by-step explanation:

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Need help on this one
ivolga24 [154]
If a triangle has side lengths 5, 5, and 8, then the triangle should be classified as isosceles.

This is because an isosceles triangle has two sides of the same length and one side of a different length. This isn’t an equilateral triangle (where all sides are of equal length) or a scalene triangle (where all sides are of different lengths).

Hope this helps!
8 0
3 years ago
Determine the intercepts of the line.<br> y-intercept (____,____)<br> x-intercept (____,____)
bija089 [108]

Answer:

y intercept is  (0 , 2.5)

x intercept is (3.5 , 0)

Step-by-step explanation:

Khan Academy is fun !!!!!!!!!!

y- intercept is where the line meets the y line    l

x- intercept is where the line meets the x line   ____

The y-intercept is 2.5

The x-intercept is 3.5

3 0
3 years ago
What is the nth term of the geometric sequence -2,10,-50
poizon [28]

Answer:

T_n=-1(-5)^n^-^1

Step-by-step explanation:

We are given;

A geometric sequence;

-2,10,-50

Required to determine the nth term

The nth term in a geometric sequence is given by the formula;

T_n=a_1r^n^-^1

where a_1 is the first term and r is the common ratio;

In this case;

a_1=-2

r = 10 ÷ -2

  = -5

Therefore;

To get the nth term in the given geometric sequence we use;

T_n=-1(-5)^n^-^1

Thus, the nth term is T_n=-1(-5)^n^-^1

3 0
3 years ago
a collection of dimes and quarters is worth $19.85. There are 128 coins in all. How many of each type of coin are in the collect
PolarNik [594]

Number of dimes were 81 and number of quarters were 47

<em><u>Solution:</u></em>

Let "d" be the number of dimes

Let "q" be the number of quarters

We know that,

value of 1 dime = $ 0.10

value of 1 quarter = $ 0.25

<em><u>Given that There are 128 coins in all</u></em>

number of dimes + number of quarters = 128

d + q = 128 ------ eqn 1

<em><u>Also given that collection of dimes and quarters is worth $19.85</u></em>

number of dimes x value of 1 dime + number of quarters x value of 1 quarter = 19.85

d \times 0.10 + q \times 0.25 = 19.85

0.1d + 0.25q = 19.85  -------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

From eqn 1,

d = 128 - q -------- eqn 3

<em><u>Substitute eqn 3 in eqn 2</u></em>

0.1(128 - q) + 0.25q = 19.85

12.8 - 0.1q + 0.25q = 19.85

12.8 + 0.15q = 19.85

0.15q = 7.05

<h3>q = 47</h3>

Therefore from eqn 3,

d = 128 - q

d = 128 - 47

<h3>d = 81</h3>

Thus number of dimes were 81 and number of quarters were 47

4 0
3 years ago
H(w)=-5x^2+80 to factored form
algol13

Answer:

- 5(x - 4)(x + 4)

Step-by-step explanation:

Given

- 5x² + 80 ← factor out - 5 from each term

= - 5(x² - 16) ← x² - 16 is a difference of squares and factors in general as

a² - b² = (a - b)(a + b), thus

x² - 16 = x² - 4² = (x - 4)(x + 4)

Thus

- 5x² + 80 = - 5(x - 4)(x + 4) ← in factored form

3 0
3 years ago
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