What is one possible solution for the triangle below?
1 answer:
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Don't sob! I gotchu!
2. c^2=5c aka c^2-5c+0=0 right?
now we need a number on the left which will multiply to give c^2, we will get that by c*c good?
now to the right side, we need numbers that multiply to give 0 and sum to -5, we'll get that by -5*0=0 and -5+0=-5 good?
now you get the factor (c-5)!
now this way, while factoring an equation that has a coefficient of more than 1, we multiply that coefficient to the constant (in the first question, 2 will be multiplied to 36 giving 72) now we need numbers that multiply to give 72 and sum to 0, since there isn't a number like that, we will have to use the quadratic formula. get it?
(also if the alphabets get too confusing, you can always use x, it doesn't matter!)
2. c^2=5c aka c^2-5c+0=0 right?
now we need a number on the left which will multiply to give c^2, we will get that by c*c good?
now to the right side, we need numbers that multiply to give 0 and sum to -5, we'll get that by -5*0=0 and -5+0=-5 good?
now you get the factor (c-5)!
now this way, while factoring an equation that has a coefficient of more than 1, we multiply that coefficient to the constant (in the first question, 2 will be multiplied to 36 giving 72) now we need numbers that multiply to give 72 and sum to 0, since there isn't a number like that, we will have to use the quadratic formula. get it?
(also if the alphabets get too confusing, you can always use x, it doesn't matter!)