We have that
A(-2,-4) B(8,1) <span>
let
M-------> </span><span>the coordinate that divides the directed line segment from A to B in the ratio of 2 to 3
we know that
A--------------M----------------------B
2 3
distance AM is equal to (2/5) AB
</span>distance MB is equal to (3/5) AB
<span>so
step 1
find the x coordinate of point M
Mx=Ax+(2/5)*dABx
where
Mx is the x coordinate of point M
Ax is the x coordinate of point A
dABx is the distance AB in the x coordinate
Ax=-2
dABx=(8+2)=10
</span>Mx=-2+(2/5)*10-----> Mx=2
step 2
find the y coordinate of point M
My=Ay+(2/5)*dABy
where
My is the y coordinate of point M
Ay is the y coordinate of point A
dABy is the distance AB in the y coordinate
Ay=-4
dABy=(1+4)=5
Mx=-4+(2/5)*5-----> My=-2
the coordinates of point M is (2,-2)
see the attached figure
Answer:
The answer is above the solid line.
Step-by-step explanation:
Answer:
The GCF for the numerical part is 2
Step-by-step explanation:
6x^2y^2-8xy^2+10xy
It contains both numbers and variables, there are two steps to find the GCF(HCF).
1). Find the GCF for the numerical part 6, -8,10
2). Find the GCF for the variable part x^2,y^2,x^1,y^2,x^1,y^3
3).Multiply the values together.
Find the common factors for the numerical part:
6,-8,10
Factors of 6
6: 1,2,3,6
Factors of -8
-8: -8,-4,-2,-1,1,2,4,8
Factors of 10
10:1,2,5,10
Common factors of 6,-8, 10 are 1,2
The GCF Numerical=2
The GCF Variable= xy^2
Multiply the GCF of the numerical part 2 and the GCF of the variable part xy^2, and you'll get 2xy^2