Answer:
The fraction of the original strip left is .
Step-by-step explanation:
We have that,
A strip of paper is cut in . So, the strip of paper left is
.
Now, again the remaining part is cut in half. The part left will be i.e.
.
Finally, the remaining part is again cut in half.
We get, the final part of the paper remaining is i.e.
.
So, the fraction of the original strip left is .
Answer:
Chukwu's share is of $57.
Step-by-step explanation:
This question is solved by a system of equations.
I am going to say that:
Chukwu's share is x.
Abdul's share is y.
Kunle's share is z.
Chukwu, Abdul and kunle are to share $142
This means that
Abdul gets $11.00 less than Chukwu
This means that:
$7.00 more than Kunle.
This means that:
So
How much is Chukwu's share?
We want to find x, so:
Chukwu's share is of $57.
Answer:
(-0.1059 ; - 0.0337)
Step-by-step explanation:
The data table is attached in the picture below:
These is a matched pair design ; which requires taking the difference of the two values for each sample :
The mean and standard deviation of the difference will be used to construct the confidence interval :
The mean of difference, dbar = Σx/n = - 0.0698
The standard deviation of difference, Sd ;
Sd = [√Σ(d - dbar)²/(n-1)] = 0.1054
n = sample size = 25
The confidence interval :
dbar ± [TCritical * Sd/√n]
Tcritical at 90% ; df = n -1 = 25 -1
Tcritical(90% , 24) = 1.1711
C.I = - 0.0698 ± (1.711 * 0.1054/√25)
C.I = - 0.0698 ± 0.0361
C.I = (-0.1059 ; - 0.0337)
Answer:
Over 2 oz. Class A-II felony
Step-by-step explanation:
One would need to carefully weigh the material.*
0.06 kg ≈ 2.12 oz
Note that .06 kg is 1 significant figure, so this rounds to 2 oz (1 significant figure). Given the precision of the reported weight, there is insufficient precision to say the amount is actually over 2 oz.
__
If you take the numbers at face value, the suspect is in possession of over 2 oz, so will be charged with a Class A-II felony.
_____
* 2.00 ounces translates to about 0.0567 kg, which rounds to 0.06 kg.
