Question

The sum of three consecutive odd integers is 18 less than 5 times the middle number. Find the 3 integers. Use an algebraic solution

Answer 1

X +(x+2) + (x+4) = 5(x+2)-18

3x+6 = 5x+10-18

3x+6 = 5x-8

3x=5x-14

-2x=-14

x=7

(x+2) =9

(x+4) =11

7 + 9+ 11 =27

5(9)-18 =45-18 =27

3 numbers are 7, 9 & 11