Answer:
Both are inverse pairs
Step-by-step explanation:
Question 11
![g(x)= 4 + \dfrac{8}{5}x](https://tex.z-dn.net/?f=g%28x%29%3D%204%20%2B%20%5Cdfrac%7B8%7D%7B5%7Dx)
(a) Rename g(x) as y
![y = 4 + \dfrac{8}{5}x](https://tex.z-dn.net/?f=y%20%3D%204%20%2B%20%5Cdfrac%7B8%7D%7B5%7Dx)
(b) Solve for x :
![\dfrac{8}{5}x = y - 4](https://tex.z-dn.net/?f=%5Cdfrac%7B8%7D%7B5%7Dx%20%3D%20y%20-%204)
(c) Multiply each side by ⅝
![x = \dfrac{5}{8}(y - 4) = \dfrac{5}{8}y - \dfrac{5}{2}](https://tex.z-dn.net/?f=x%20%3D%20%5Cdfrac%7B5%7D%7B8%7D%28y%20-%204%29%20%3D%20%5Cdfrac%7B5%7D%7B8%7Dy%20-%20%5Cdfrac%7B5%7D%7B2%7D)
(d) Switch x and y
![y = \dfrac{5}{8}x - \dfrac{5}{2}](https://tex.z-dn.net/?f=y%20%3D%20%5Cdfrac%7B5%7D%7B8%7Dx%20-%20%5Cdfrac%7B5%7D%7B2%7D)
(e) Rename y as the inverse function
![g^{-1}(x) = \dfrac{5}{8}x - \dfrac{5}{2}](https://tex.z-dn.net/?f=g%5E%7B-1%7D%28x%29%20%3D%20%5Cdfrac%7B5%7D%7B8%7Dx%20-%20%5Cdfrac%7B5%7D%7B2%7D)
(f) Compare with your function
![f(x) = \dfrac{5}{8}x - \dfrac{5}{2}\\\\f(x) = g^{-1}(x)](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Cdfrac%7B5%7D%7B8%7Dx%20-%20%5Cdfrac%7B5%7D%7B2%7D%5C%5C%5C%5Cf%28x%29%20%3D%20g%5E%7B-1%7D%28x%29)
f(x) and g(x) are inverse functions.
The graphs of inverse functions are reflections of each other across the line y = x.
In the first diagram, the graph of ƒ(x) (blue) is the reflection of g(x) (red) about the line y = x (black)
Question 12
h(x)= x - 2
(a) Rename h(x) as y
y = x - 2
(b) Solve for x:
x = y + 2
(c) Switch x and y
y = x + 2
(e) Rename y as the inverse function
h⁻¹(x) = x + 2
(f) Compare with your function
f(x) = x + 2
f(x) = h⁻¹(x)
h(x) and ƒ(x) are inverse functions.
The graph of h(x) (blue) reflects ƒ(x) (red) across the line y = x (black).
Represent 'a number' by x
7 times x equals 9 more than 4 times x
7 times x=9+4 times x
7x=9+4x
subtract 4x from both sides
3x=9
divide 3
x=3
the number is 3
Answer:
I've been trying to figure this out with out a chart and i keep confusing myself
Step-by-step explanation:
nothing
The expression that gives an angle that is coterminal with 126 is 126 + 720n. Two angles are said to be coterminal if when they are drawn in a standard position, their terminal sides are on the same location. The expression will give an angle which when it is drawn the terminal sides are on the same location with the 126 angle.